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djyliett [7]
3 years ago
10

If oranges cost $0.75 for 1/3 of a dozen, how many oranges can you buy for $3.00?? ❗️Please help❗️

Mathematics
2 answers:
kramer3 years ago
8 0
1/3 of a dozen o =(1/3)12=12/3=4 (oranges).
$0.75 / 4 oranges=$3.00 / x
x=($3.00)(4 oranges) / $0.75=16 oranges.

answer: 16 oranges. 


pishuonlain [190]3 years ago
6 0
75 + 75 + 75. = 2.25 so no
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Answer:

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Step-by-step explanation:

Let

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Numerator = 2(b^2+a^2)    or equivalently 2b^2+2a^2

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4 0
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PLEASE HELP ME!! Simplify by multiplying the LCD
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