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3 years ago

Is a copper wire a conductor or insulator?

2 answers:

6 0

A copper wire is a "conductor." Metals are usually conductors because they attract electricity. But, non-metals such as oxygen or carbon would be good insulators.

Hope this helps.

irina [24]3 years ago

5 0

Answer:

its a conductor because it conducts electricity

Explanation:

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1. Explain one way gravity affects objects.

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Answer:

it makes it fall to the ground instead of float

Explanation:

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3 years ago

A soccer ball is sitting in the middle of a soccer field during a game. When the referee blows his whistle, one of the players r

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Before its moving it should be 0 right

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3 years ago

Read 2 more answers

A spaceship negotiates a circular turn of radius 2925 km at a speed of 29960 km/h. (a) What is the magnitude of the angular spee

emmainna [20.7K]

a) 0.0028 rad/s

b) $23.68 m/s^2$

c) $0 m/s^2$

Explanation:

When an object is in circular motion, the angular speed of the object is the rate of change of its angular position. In formula, it is given by

$\omega = \frac{\theta}{t}$

where

$\theta$ is the angular displacement

t is the time interval

The angular speed of an object in circular motion can also be written as

$\omega = \frac{v}{r}$ (1)

where

v is the linear speed of the object

r is the radius of the orbit

For the spaceship in this problem we have:

$v=29,960 km/h$ is the linear speed, converted into m/s,

$v=8322 m/s$

$r=2925 km = 2.925\cdot 10^6 m$ is the radius of the orbit

Subsituting into eq(1), we find the angular speed of the spaceship:

$\omega=\frac{8322}{2.925\cdot 10^6}=0.0028 rad/s$

When an object is in circular motion, its direction is constantly changing, therefore the object is accelerating; in particular, there is a component of the acceleration acting towards the centre of the orbit: this is called centripetal acceleration, or radial acceleration.

The magnitude of the radial acceleration is given by

$a_r=\omega^2 r$

where

$\omega$ is the angular speed

$r$ is the radius of the orbit

For the spaceship in the problem, we have

$\omega=0.0028 rad/s$ is the angular speed

$r=2925 km = 2.925\cdot 10^6 m$ is the radius of the orbit

Substittuing into the equation above, we find the radial acceleration:

$a_r=(0.0028)^2(2.925\cdot 10^6)=23.68 m/s^2$

When an object is in circular motion, it can also have a component of the acceleration in the direction tangential to its motion: this component is called tangential acceleration.

The tangential acceleration is given by

$a_t=\frac{\Delta v}{\Delta t}$

where

$\Delta v$ is the change in the linear speed

$\Delta t$ is the time interval

In this problem, the spaceship is moving with constant linear speed equal to

$v=8322 m/s$

Therefore, its linear speed is not changing, so the change in linear speed is zero:

$\Delta v=0$

And therefore, the tangential acceleration is zero as well:

$a_t=\frac{0}{\Delta t}=0 m/s^2$

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3 years ago

Quel est le gaz présent dans la couche d’ozone

stepan [7]

Answer:

L'ozone est produit à partir du dioxygène, composé de deux atomes d'oxygène(O2). Aux altitudes supérieures à 30 km, le rayonnement solaire possède encore une énergie suffisante pour casser une partie des molécules de dioxygène et libérer les atomes

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3 years ago

A bus starts from rest and accelerates to 14 m/s in 4 s. What is the

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Acceleration = 14/4 = ....

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4 years ago