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lakkis [162]
3 years ago
13

If you pluck a guitar string hard the sound waves it gives off will have __________ amplitudes.

Physics
2 answers:
lions [1.4K]3 years ago
6 0

large

Explanation:

the harder you pluck the louder it get

Ilia_Sergeevich [38]3 years ago
4 0

Answer:

large

Explanation:

the harder you pluck the louder it gets

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Two masses are connected by a string which passes over a pulley with negligible mass and friction. One mass hangs vertically and
monitta

Answer:

a=2,5m/s^2

Explanation:

From the question we are told that:

Coefficient of kinetic friction \mu= 0.200

Vertical Mass M_v=3kg

Horizontal mass M_h=3.00kg  

Generally the equation for kinetic force F_k is mathematically given by

F_k=\mu N\\F_k=0.2*3\\F_k=0.6

Generally the equation for T is mathematically given by

For M_v=3kg3g-T=3a

For M_h=3kg

T=M_v V+F_k\\T=3.0a+0.6

Therefore substituting

3-3a-0.6=3a\\2.4g=6a

a=2,5m/s^2

3 0
3 years ago
Anakin Skywalker's pod racer has a mass of 450 kg. If the top speed of this racer is 947
andriy [413]

Answer:

15,569,653.3 Joules(J)

Explanation:

The equation used to find Kinetic Energy (KE) is

KE = \frac{1}{2} m v^{2}

You have been given

m = 450kg

v = 947km/h

KE = ???

Firstly, we need to convert the km/h into m/s as this is the unit used in the KE equation

This can be done by dividing by 3.6

947km/h = 263.056m/s

Substitute you values into the equation

KE = \frac{1}{2} m v^{2}

KE = \frac{1}{2} * 450 * 263.056^{2}

KE = 15,569,653.3 Joules(J)

Round your answer as appropriate

3 0
3 years ago
An attacker at the base of a castle wall 3.95 m high throws a rock straight up with speed 5.00 m/s from a height of 1.60 m above
s344n2d4d5 [400]

Answer:

a) No

b) the rock must have a minimum initial speed of 6.79m/s for it to reach the top of the building.

Explanation:

Given:

Height of the wall = 3.95m

Initial height = 1.60m

Initial speed = 5.00m/s

distance between the initial height and wall top = 3.95 - 1.60 = 2.35m

Using the formula;

v^2 = u^2 + 2as ....1

Where v = final velocity, u = initial velocity, a = acceleration, s = distance travelled

From equation 1

s = (v^2 - u^2)/2a ...2

Since the rock t moving up,

the acceleration = -g = -9.8m/s2

s = maximum height travelled

v = 0 (at maximum height velocity is zero)

Substituting into equation 2

s = (0 - 5^2)/(2×-9.8) = 1.28m

Therefore, the maximum height is 1.28 from his initial height Which is less than the 2.35m of the wall from his initial height. So the rock will not reach the top of the wall

b) Using equation 1:

u^2 = v^2 - 2as

v = 0

a = -9.8m/s

s = 2.35m. (distance between the initial height and wall top)

u^2 = 0 - 2(-9.8 × 2.35)

u^2 = 46.06

u = √46.06

u = 6.79m/s

Therefore, the rock must have a minimum initial speed of 6.79m/s

8 0
3 years ago
two forces are acting on a wheelbarrow. One force is pushing to the right and an equal force is pushing to the left. What can yo
ICE Princess25 [194]
B it is not accelerating
3 0
3 years ago
Read 2 more answers
Atoms with the same number of protons but different numbers of neutrons are called isomers
Ludmilka [50]
False, atoms with the the same number of protons but a differing number of neutrons is called an isotope.

An isomer is a compound that has the same atomic makeup as another, but in a different arrangement.
8 0
3 years ago
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