<span>(Problem Number Five Answer: Simplify exponent so you get -3)
(Problem Number Seven Answer:
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Step 1: Simplify brackets
Step 2: <span>Gather like terms
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Step 3: Use Product Rule
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Step 4: </span>Simplify 2+1 to 3
Step 5: Simplify 3 + 1 to 4
Step 6: <span>Simplify
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Done! :)
(Problem Number 9 answer: Simplify the exponent so you get -5 )
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Answer:
The measure of the perpendicular KD is 8.72 unit .
Step-by-step explanation:
Given as :
The triangle AKM , with KD perpendicular to AM
The measure of side AK = 6 unit
The measure of side KM = 10 unit
The ∠ AKM = 93°
Let The measure of side KD = x unit
Now,
∵ KD ⊥ AM , KD divide the angle ∠ AKM equally
So, ∠ AKD = ∠ 
I.e ∠ AKD = ∠ 
∴ ∠ AKD = 46.5°
Now, Again
Cos Ф = 
I.e Cos 46.5° = 
I.e 0.688 =
∴ KD = 
I.e KD = 8.72 unit
Hence The measure of the perpendicular KD is 8.72 unit Answer
Answer: x = 8/5
Explanation:
5x-2 = 6
5x = 6 + 2
5x = 8
x = 8/5
<span>1) Write the point-slope form of the equation of the horizontal line that passes through the point (2, 1). y = 1/2x
2)Write the point-slope form of the equation of the line that passes through the points (6, -9) and (7, 1).
m = (-9 - 1) / (6 - 7) = -10/-1 = 10
y + 9 = 10 (x - 6)
y = 10x - 69
3) A line passes through the point (-6, 6) and (-6, 2). In two or more complete sentences, explain why it is not possible to write the equation of the given line in the traditional version of the point-slope form of a line.
4)Write the point-slope form of the equation of the line that passes through the points (-3, 5) and (-1, 4).
m = (5 - 4) / (-3 - -1) = 1/-2
y - 5 = (-1/2) (x +3)
y = (-1/2)x + 7/2
5) Write the point-slope form of the equation of the line that passes through the points (6, 6) and (-6, 1).
m = (6-1)/(6 - -6) = 5 / 12
y - 6 = (5/12) (x-6)
y = (5/12)x + 17 / 2
6) Write the point-slope form of the equation of the line that passes through the points (-8, 2) and (1, -4).
m = (2 - -4) / (-8 -1) = 6 / -7
y - 2 = (-6/7) (x + 8)
y = (-6/7)x - 50 / 7
7) Write the point-slope form of the equation of the line that passes through the points (5, -9) and (-6, 1).
m = (-9 - 1) / (5 - -6) = -10 / 11
y + 9 = (-10 / 11) (x - 5)
y = (-10 / 11)x -49/11
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