Answer:
10 cm.
Step-by-step explanation:
We'll begin by calculating the area of the small bubble. This can be obtained as follow:
Radius (r) = 5 cm
Area (A) =?
Since the bubble is circular in nature, we shall use the formula for area of circle to determine the area of the bubble. This is illustrated below:
A = πr²
A = π × 5²
A = 25π cm²
Next, we shall determine the total area of the small bubbles. This can be obtained as follow:
Area of 1 bubble = 25π cm²
Therefore,
Area of 4 bubbles = 4 × 25π cm²
Area of 4 bubbles = 100π cm²
Finally, we shall determine the radius of the large bubble. This can be obtained as follow:
Area of large bubble = total area of small bubbles = 100π cm²
Radius (r) =?
A = πr²
100π = πr²
100 = r²
Take the square root of both side
r = √100
r = 10 cm
Thus, the radius of the large bubble is 10 cm
(84x - 69y) - (65x + 34y)
Remove the parenthesis and combine the like terms:
84x - 65x = 19x
-69y - 34y = -103y
Combine for final answer:
19x -103y
Answer:
45q + 35
Step-by-step explanation:
In 3 metres there are 300 centimetres. Each centimetre on the scale is 300 centimeters, or a ratio of 1:300. The tree is 5 centimetres on the scale. Each centimeter on the scale is 300 centimetres, therefore 5 centimetres on the scale is 1500 centimetres. 1500 centimetres is equal to 15 metres.
From the calculation, the growth rate is 0.88.
<h3>What is the growth rate?</h3>
To find the relative growth rate
P1 = Poe^rt
P2 = Poe^rt
Thus;
1920 = Poe^4r ------ (1)
1966080 =Poe^12r -------(2)
P2/P1 gives;
1966080/1920 = Poe^12r/Poe^4r
1024 = e^12r/e^4r
1024 =e^8r
1024 = (e^r)^8
2^10 = (e^r)^8
e^r = 2^1.25
e^r = 2.38
r = ln(2.38)
r = 0.88
The initial size of the culture is;
1920 = Poe^(0.88 * 4)
Po = 1920/e^(0.88 * 4)
Po = 57
The expression for the exact number of bacteria after t hours is
P(t) = 57e^0.08t
The growth (in bacteria per hour) after 9.5 hours is
P(t) = 57e^(0.88 * 9.5)
P(t) = 243544
For the number to reach 72,000;
72,000 = 57e^0.88t
72,000/57 = e^0.88t
ln 126 = ln[e^0.88t]
4.8 = 0.88t
t = 4.8/0.88
t = 5.5 hours
Learn more about exponential growth;brainly.com/question/13674608
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