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Alja [10]
3 years ago
12

(90 PTS) PLS HELP ME!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!What type of environment do sedimentary rocks form in? Wher

e do metamorphic rocks form? Keep in mind the rocks at the Great Unconformity when answering. Explain in 2-4 sentences
Chemistry
2 answers:
miv72 [106K]3 years ago
4 0

Sedimentary Rocks: You can find different types in riverbeds, ponds and coasts and throughout the oceans.

Metamorphic rocks: They can be formed by pressures deep inside the Earth.

Savatey [412]3 years ago
3 0

Sedimentary rocks form where there is water, like streams, rivers and the coast. At the Great Unconformity, sedimentary rocks form near the top as they are younger.


Metamorphic rocks form where there is extreme pressure and/or heat, such as deep underground or in a volcano.  At the Great Unconformity, metamorphic rocks are at the bottom as they are older.


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14-6=8
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From a scientific viewpoint, why do many desert dwellers elect to wear white or light-colored garments
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Judging by the electron domain geometry, which type of hybrid orbitals does this molecule have? s sp sp2 sp3
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The molecule have TETRAHEDRAL HYBRID ORBITAL.
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Read 2 more answers
For the following reaction, 4.31 grams of iron are mixed with excess oxygen gas . The reaction yields 5.17 grams of iron(II) oxi
natka813 [3]

<u>Answer:</u> The theoretical yield of iron (II) oxide is 5.53g and percent yield of the reaction is 93.49 %

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}       ....(1)

  • <u>For Iron:</u>

Given mass of iron = 4.31 g

Molar mass of iron = 53.85 g/mol

Putting values in above equation, we get:  

\text{Moles of iron}=\frac{4.31g}{53.85g/mol}=0.0771mol

For the given chemical reaction:

2Fe(s)+O_2(g)\rightarrow 2FeO(s)

By Stoichiometry of the reaction:

2 moles of iron produces 2 moles of iron (ii) oxide.

So, 0.0771 moles of iron will produce = \frac{2}{2}\times 0.0771=0.0771mol of iron (ii) oxide

Now, calculating the theoretical yield of iron (ii) oxide using equation 1, we get:

Moles of of iron (II) oxide = 0.0771 moles

Molar mass of iron (II) oxide = 71.844 g/mol

Putting values in equation 1, we get:  

0.0771mol=\frac{\text{Theoretical yield of iron(ii) oxide}}{71.844g/mol}=5.53g

To calculate the percentage yield of iron (ii) oxide, we use the equation:

\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100

Experimental yield of iron (ii) oxide = 5.17 g

Theoretical yield of iron (ii) oxide = 5.53 g

Putting values in above equation, we get:

\%\text{ yield of iron (ii) oxide}=\frac{5.17g}{5.53g}\times 100\\\\\% \text{yield of iron (ii) oxide}=93.49\%

Hence, the theoretical yield of iron (II) oxide is 5.53g and percent yield of the reaction is 93.49 %

7 0
3 years ago
The atomic theory proposed by dalton has been
Sidana [21]

What did Dalton's atomic theory contribute to science?

Dalton's atomic theory proposed that all matter was composed of atoms, indivisible and indestructible building blocks. While all atoms of an element were identical, different elements had atoms of differing size and mass.

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4 years ago
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