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Alja [10]
3 years ago
12

(90 PTS) PLS HELP ME!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!What type of environment do sedimentary rocks form in? Wher

e do metamorphic rocks form? Keep in mind the rocks at the Great Unconformity when answering. Explain in 2-4 sentences
Chemistry
2 answers:
miv72 [106K]3 years ago
4 0

Sedimentary Rocks: You can find different types in riverbeds, ponds and coasts and throughout the oceans.

Metamorphic rocks: They can be formed by pressures deep inside the Earth.

Savatey [412]3 years ago
3 0

Sedimentary rocks form where there is water, like streams, rivers and the coast. At the Great Unconformity, sedimentary rocks form near the top as they are younger.


Metamorphic rocks form where there is extreme pressure and/or heat, such as deep underground or in a volcano.  At the Great Unconformity, metamorphic rocks are at the bottom as they are older.


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V ∝ n  

Step-by-step explanation:

Suppose that pressure and temperature are constant.

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The hydrogen chloride (HCl) molecule has an internuclear separation of 127 pm (picometers). Assume the atomic isotopes that make
natta225 [31]

Answer:

the energy of the third excited rotational state \mathbf{E_3 = 16.041 \ meV}

Explanation:

Given that :

hydrogen chloride (HCl) molecule has an intermolecular separation of 127 pm

Assume the atomic isotopes that make up the molecule are hydrogen-1 (protium) and chlorine-35.

Thus; the reduced mass μ = \dfrac{m_1 \times m_2}{m_1 + m_2}

μ = \dfrac{1 \times 35}{1 + 35}

μ = \dfrac{35}{36}

∵ 1 μ = 1.66 × 10⁻²⁷ kg

μ  = \\ \\ \dfrac{35}{36} \times 1.66 \times 10^{-27} \ \  kg

μ  = 1.6139 × 10⁻²⁷ kg

r_o = 127 \ pm = 127*10^{-12} \ m

The rotational level Energy can be expressed by the equation:

E_J = \dfrac{h^2}{8 \pi^2 I } \times J ( J +1)

where ;

J = 3 ( i.e third excited state)  &

I = \mu r^2_o

E_J= \dfrac{h^2}{8  \pi  \mu r^ 2 \mur_o } \times J ( J +1)

E_3 = \dfrac{(6.63 \times 10^{-34})^2}{8  \times  \pi ^2  \times 1.6139 \times 10^{-27} \times( 127 \times 10^{-12}) ^ 2  } \times 3 ( 3 +1)

E_3= 2.5665 \times 10^{-21} \ J

We know that :

1 J = \dfrac{1}{1.6 \times 10^{-19}}eV

E_3= \dfrac{2.5665 \times 10^{-21} }{1.6 \times 10^{-19}}eV

E_3 = 16.041  \times 10 ^{-3} \ eV

\mathbf{E_3 = 16.041 \ meV}

8 0
3 years ago
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