<span>Given in the question-
1 mole of cyclohexanol = > 1 mole of cyclohexene
Molar mass 100.16 g/mol
moles of cyclohexanol = .240 / 100.16= 0.002396 moles
Molar mass 82.143 g/mol
moles of cyclohexene formed @100 % yield = 0.002396
Molar mass 82.143 g/mol
mass of cyclohexene @ 100 % = .002396 x 82.143 = 0.197g
bur we have .138g
so % yield = .138 / .197 = 70.0 %
Ans- 70 percentage yield of cyclohexene.</span>
Answer:
icicle becausit sounds right
Explanation:
icicles because it sounds right
Answer:
Explanation:
The formula of the reaction:
KClO₂ → KCl + O₂
To assign oxidation numbers, we have to obey some rules:
- Elements in an uncombined state or one whose atoms combine with one another to form molecules have an oxidation number of zero.
- The charge on simple ions signifies their oxidation number.
- The algebraic sum of all the oxidation number of all atoms in a neutral compound is zero. For radicals with charges, their oxidation number is the charge.
The oxidation number of K in KClO₂:
K + (-1) + 2(-2) = 0
K-5 = 0
K = +5
The oxidation number of K in KCl:
K + (-1) = 0
K = +1
The oxidation number Cl in KClO₂ is -1
For Cl in KCl, the oxidation number is -1
For O in KClO₂, the oxidation number is (2 x -2) = -4
For O in O₂, the oxidation number is 0
K moves from an oxidation state of +5 to +1. This is a gain of electrons and K has undergone reduction. We then say K is reduced.
O moves from an oxidation state of -4 to 0. This is a loss of electrons and O has undergone oxidation. We say O is oxidized.
Molarity's formula is known as: Molarity(M)=moles of solute/liters solution.
In this case we are already given moles and liters so you just have to plug the numbers into the equation.
0.400 mol HCL/9.79L solution=0.040858M
If you were to use scientific notation, the answer will be: 4.1*10^-2, but otherwise, you can just use the decimals above and round appropriately as you see fit.
