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deff fn [24]
3 years ago
9

Which best protects animal species that are endangered due to overhunting?

Chemistry
2 answers:
a_sh-v [17]3 years ago
7 0

Answer:

captive breeding

Explanation:

jekas [21]3 years ago
3 0

Answer:

Captive breeding

Explanation:

Endangered species, such as the Black Rhino, Saola, Cross River Gorrillas, the Blue Whale, and a host of others, are species that are critically under the verge of extinction either as a result of the destruction of their habitat or poaching/overhunting, which has really led to steep decline in their population.

Several attempts have been made and ate being made to ensure the preserve and protect these endangered species form going extinct.

However, the best of such measures or practices is arguably referred to as Captive Breeding.

Captive breeding involves the capturing of some of these endangered species and transporting them to enclosed and monitored facilities such as zoos in other to promote the increase preservation and survival of these species and ensuring they don't go extinct.

In most cases, when a considerable increase in population in these facilities is established through breeding, some of them are later on reintroduced to their natural habitat in the wild. This do not only ensure biodiversity, it also ensures the population of the endangered species to grow and avoid such species from going extinct.

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how many molecules of sulfuric acid are in a spherical raindrop of diameter 6.0 mm if the acid rain has a concentration of 4.4 *
Vitek1552 [10]

Answer:

The number of moles =

Moles=4.97\times 10^{-8}

The number of molecules =

Molecules = 2.99\times 10^{16}

Explanation:

Volume of the sphere is given by :

V=\frac{4}{3}\pi r^{3}

here, r = radius of the sphere

radius=\frac{diameter}{2}

radius=\frac{6.0}{2}

Radius = 3 mm

r = 3 mm

1 mm = 0.01 dm (1 millimeter = 0.001 decimeter)

3 mm = 3 x 0.01 dm = 0.03 dm

r = 0.03 dm

<em>("volume must be in dm^3 , this is the reason radius is changed into dm"</em>

<em>"this is done because 1 dm^3 = 1 liter and concentration is always measured in liters")</em>

V=\frac{4}{3}\pi 0.03^{3}

V=\frac{4}{3}\pi 2.7\times 10^{-5}

V=1.13\times 10^{-4}dm^{3}

V=1.13\times 10^{-4}L   (1 L = 1 dm3)

Now, concentration "C"=

C=4.4\times 10^{-4}moles/liter  

The concentration is given by the formula :

C=\frac{moles}{Volume(L)}

This is also written as,

Moles = C\times Volume

Moles=1.13\times 10^{-4}\times 4.4\times 10^{-4}

Moles=4.97\times 10^{-8}moles

One mole of the substance contain "Na"(= Avogadro number of molecules)

So, "n"  mole of substance contain =( n x Na )

N_{a}=6.022\times 10^{23}

Molecules =

Molecule=4.97\times 10^{-8}\times 6.022\times 10^{23}

Molecules = 2.99\times 10^{16} molecules

7 0
3 years ago
How many moles in 34.2 g of sulfur?
BigorU [14]
1.07 mol would be your answer
7 0
4 years ago
4. What is the bridge that allows you to convert from the given substance to the wanted substance
Dmitry_Shevchenko [17]
I’m not sure if this is what you are referring to but there is something called a moles bridge which allows you to convert from one substance to another
6 0
3 years ago
How many distinct dichlorination products can result when isobutane is subjected to free radical chlorination?
Elenna [48]

Answer:

c. 3

Explanation:

Dicholorination of tertiary alkane ( i.e. isobutane) is a halogenation reaction which makes it possible to replace the alkyl functional group with halogenated chlorine.

When Isobutane is subjected to free radicals chlorination, three distinct dichlorination can be formed.

The mechanism of the formation of these products can be seen in the image attached below.

4 0
4 years ago
SOMEBODY PLEASE HELPP I HAVE LIKE 10 TEST THAT I HAVE TO TAKE AND I WAS OUT SICK THOSE DAYS
snow_lady [41]

Answer: the 1st one is B, 2 is A, 3 is A, 4 is a or D for this one, 5 is c, 6 is b, 7 is b, 8 is d, 9 is a, 10 is b those are my best guess and if that did work I'm sorry I didn't help you and take care also have a great day.

4 0
3 years ago
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