Answer:
precipitation then condensation
Step-by-step explanation:
Answer:
z= 3.63
z for significance level = 0.05 is ± 1.645
Step-by-step explanation:
Here p = 42% = 0.42
n= 500
We formulate our null and alternative hypotheses as
H0: p= 0.42 against Ha : p> 0.42 One tailed test
From this we can find q which is equal to 1-p= 1-0.42 = 0.58
Taking p`= 0.5
Now using the z test
z= p`- p/ √p(1-p)/n
Putting the values
z= 0.5- 0.42/ √0.42*0.58/500
z= 0.5- 0.42/ 0.0220
z= 3.63
For one tailed test the value of z for significance level = 0.05 is ± 1.645
Since the calculated value does not fall in the critical region we reject our null hypothesis and accept the alternative hypothesis that more than 42% people owned cats.
Answer:
multiple choice is worth 2
short response is worth 4
Step-by-step explanation:
23x + 10y = 86
28x + 5y = 76
solve by elimination
multiply the top by -1 and the bottom by 2
-23x + -10y = -86
56x + 10y = 152
add them
33x = 66
x = 2
with x = 2 plug x into one of the equations
23x + 10y = 86
23(2) + 10y = 86
46 + 10y = 86
10y = 40
y = 4
x = 2 and y = 4 so
multiple choice is worth 2
short response is worth 4