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artcher [175]
3 years ago
12

I need the answer pleaseee i cant figure out how to do this

Mathematics
1 answer:
Kipish [7]3 years ago
6 0
319.62. You get that by multiplying the perimeter. Please mark brainliest if this was helpful and have a blessed day! <3
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A sample of restaurants in a city shows that the average cost of an appetizer is $6.32 with a standard deviation of
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Costa is planning a lunch banquet. The equation C=450+28g models the relation between the cost in dollars, C, of the banquet and
algol13

Answer:

When the number of guests is 0, the cost would be $450.

Step-by-step explanation:

We have been given an equation C=450+28g, which models the relation between the cost in dollars, C, of the banquet and the number of guests, g.

We can see that our given equation in slope-intercept form of equation y=mx+b, where, m represents slope of line and b represents y-intercept or initial value.

We can see that slope for our given equation is 28 and the C-intercept is 450.

The C-intercept tells us that when there are 0 guests in the banquet, the cost would be $450.

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3 years ago
Suppose the number of inches of rainfall each year in a city is normally distributed. For a random sample of years, the confiden
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Answer:

The confidence interval for the mean is given by the following formula:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

Or equivalently:

\bar X \pm ME

For this case we have the interval given (3.9, 7.7) and we want to find the margin of error. Using the property of symmetry for a confidence interval we can estimate the margin of error with this formula:

ME= \frac{Upper -Lower}{2}= \frac{7.7-3.9}{2}= 1.9

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

Or equivalently:

\bar X \pm ME

For this case we have the interval given (3.9, 7.7) and we want to find the margin of error. Using the property of symmetry for a confidence interval we can estimate the margin of error with this formula:

ME= \frac{Upper -Lower}{2}= \frac{7.7-3.9}{2}= 1.9

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3 years ago
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