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sineoko [7]
1 year ago
8

Draw Line HI perpendicular to Line JK (be sure to include appropriate markings)

Mathematics
1 answer:
kirill [66]1 year ago
4 0

To draw line HI perpendicular to JK we need to follow the given steps:

Place your compass on the given point (point H). Draw an arc across the line on each side of the given point. Do not adjust the compass width when drawing the second arc.

From each arc on the line, draw another arc on the opposite side of the line from the given point (H). The two new arcs will intersect.

Use your ruler to join the given point (H) to the point where the arcs intersect (I).

HI is perpendicular to JK.

What is perpendicular?

Two distinct lines intersecting each other at 90°, or a right angle, are called perpendicular lines.

Properties of Perpendicular Lines

  • These lines always intersect at right angles.
  • If two lines are perpendicular to the same line, they are parallel to each other and will never intersect.
  • Adjacent sides of a square and a rectangle are always perpendicular to each other.
  • The sides of the right-angled triangle enclosing the right angle are perpendicular to each other.

To learn more about perpendicular lines,

brainly.com/question/1202004

#SPJ9

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Ilya [14]
I would say A.

B would be Carly's age is two years more than three times his sister's age.

C would be Carly's age is two times his sister's age plus three

D would be Carly's age is his sister's age squared plus three.
5 0
2 years ago
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jackson had 1 and 1/3 gallons of juice he poured 5/6 gallon to share with his friends how much of the juice is left
FromTheMoon [43]
1 1/3 - 5/6

Find common demoninator which is 6.

Then do 2*1=2.

Now you got 2/6 - 5/6 = -3/6

Simplify:

-3/6=-1/2

Then combined answers.

1 - 1/2 = 1/2

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6 0
3 years ago
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A school is preparing a trip for 400 students. The company who is providing the transportation has 10 buses of 50 seats each and
Naya [18.7K]
<h2>The number of small buses used = 5</h2><h2>The number of big buses used  = 4</h2>

Step-by-step explanation:

Let us assume the total number of small buses needed = x

The capacity of 1 small bus  = 40

So, the capacity of x buses  = 40(x)  = 40 x

Let us assume the total number of big buses needed = y

The capacity of 1 big bus  = 50

So, the capacity of y buses  = 50(y)  = 50 y

Also, the total students travelling = 400

So, the number of students traveling by (Small bus + Big bus)  = 400

⇒ 40 x + 50 y = 400 ..... (1)

Also, the total number of drivers available  = 9

⇒ x +  y = 9  ..... (2)

Also, x  ≤ 8,   y ≤ 10

Now, solving both equations, we get:

40 x + 50 y = 400 ..... (1)

x +  y = 9  ⇒ y = (9-x) put in (1)

40 x + 50 y = 400  ⇒  40 x  + 50 (9-x)  = 400

or, 40 x  + 450 - 50 x  = 400

or, - 10 x  =- 50

or, x  = 5 ⇒ y = (9-x)  = 9- 5 = 4

Hence the number of small buses used = 5

The number of big buses used  = 4

8 0
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in a fish tank, of the fish were orange and 5/100 of the fish were striped. what fraction of the fish were orange striped
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1/20 were striped if you want that as a decimal it would be 0.05 :)
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