Ask question

Ask question

All categories

3 years ago

7

A group of friends on a camping trip has 3 2/5 lb of trail mix. They devide it up evenly among themselves. Each person gets 1/5

lb of the trail mix. How many friends are on the camping trip?

1 answer:

olga_2 [115]3 years ago

6 0

Answer: 17 people

3/(1/5) + (2/5)/(1/5) = 3*5+2=17

You might be interested in

6b x 3 =<br><br> PLEAS HELP ME

MArishka [77]

18 bytes looked it up online lol

4 0

3 years ago

What is the best name for the part of the figure identified by

BigorU [14]

It is Line of symmetry

3 0

3 years ago

Read 2 more answers

What is α, the probability of a Type I error if the null hypothesis, H0, is: Carmin believes that her chemistry exam will only c

baherus [9]

Answer:

The probability of falling into a type I error, when testing a hypothesis test, consists of:

Probability of rejecting the null hypothesis when, in reality, this hypothesis is true.

Probability of rejecting the null hypothesis when, in reality, this hypothesis is true, is:

Probability of Affirm that Chemistry exam will NOT cover only chapters four and five, since the Chemistry exam will cover only chapters four and five.

That is, alpha is the probability that Carmin decides to study additional chapters, unnecessarily.

Step-by-step explanation:

8 0

3 years ago

Evaluate the line integral, where C is the given curve. (x + 6y) dx + x2 dy, C C consists of line segments from (0, 0) to (6, 1)

Dima020 [189]

Split $C$ into two component segments, $C_1$ and $C_2$ , parameterized by

$\mathbf r_1(t)=(1-t)(0,0)+t(6,1)=(6t,t)$

$\mathbf r_2(t)=(1-t)(6,1)+t(7,0)=(6+t,1-t)$

respectively, with $0\le t\le1$ , where $\mathbf r_i(t)=(x(t),y(t))$ .

We have

$\mathrm d\mathbf r_1=(6,1)\,\mathrm dt$

$\mathrm d\mathbf r_2=(1,-1)\,\mathrm dt$

where $\mathrm d\mathbf r_i=\left(\dfrac{\mathrm dx}{\mathrm dt},\dfrac{\mathrm dy}{\mathrm dt}\right)\,\mathrm dt$

so the line integral becomes

$\displaystyle\int_C(x+6y)\,\mathrm dx+x^2\,\mathrm dy=\left\{\int_{C_1}+\int_{C_2}\right\}(x+6y,x^2)\cdot(\mathrm dx,\mathrm dy)$

$=\displaystyle\int_0^1(6t+6t,(6t)^2)\cdot(6,1)\,\mathrm dt+\int_0^1((6+t)+6(1-t),(6+t)^2)\cdot(1,-1)\,\mathrm dt$

$=\displaystyle\int_0^1(35t^2+55t-24)\,\mathrm dt=\frac{91}6$

6 0

3 years ago

Which expressions are polynomials?

cupoosta [38]

<em><u>The expressions that are polynomial are:</u></em>

6 + w

$2x^4 - y$

z + 1

<em><u>Solution:</u></em>

A polynomial is an expression with variables and coefficients with the operations of addition, subtraction, multiplication, and non-negative integer exponents of variables

1) 6 + w

Here "w" is a variable, hence it is a polynomial expression

$2)\ 2x^4 - y$

This is a polynomial, since it has variables and coefficients and variable with non negative exponent

3) z + 1

This is also a polynomial with variable "z" and has addition operation

$4)\ y^2 - y\sqrt{3} + 4$

Since it has root so it is not a polynomial

6 0

3 years ago

Read 2 more answers