Question

Pursued by ferocious wolves, you are in a sleigh with no horses, gliding without friction across an ice-covered lake. You take an action described by the equations(270kg)(7.50m/s) i^ = (15.0 kg) (-v₁f i^) + (255kg) (v₂f i^) v₁fi^ + v₂f i^ = 8.00 m/s(b) Find the values of v₁f and v₂f .

Answer 1

$The given equations is \begin{aligned}&(270 \mathrm{~kg})(7.5 \mathrm{~m} / \mathrm{s}) \hat{1}=(15 \mathrm{~kg})\left(-\mathrm{v}_{1 \mathrm{f}} 1\right)+(255 \mathrm{~kg})\left(\mathrm{v}_{2 \mathrm{f}}{ }^{\hat{1}}\right) \\&2025=15\left(-\mathrm{v}_{1 \mathrm{f}}+\mathrm{v}_{2 \mathrm{f}}\right) \\&135=-\mathrm{v}_{1 \mathrm{f}}+\mathrm{v}_{2 \mathrm{f}} \\&\text { And } \\&\mathrm{v}_{1 \mathrm{f}}+\mathrm{v}_{2 \mathrm{f}}=8\end{aligned}$

$Adding both the equation we will get 2 \mathrm{v}_{2 \mathrm{f}}=135+8 \mathrm{v}_{2 \mathrm{f}}=71.5 \mathrm{~m} / \mathrm{s} \\Substituting above value in in any equation we will get \mathrm{v}_{1 \mathrm{f}}=8-71.5 \mathrm{v}_{1 \mathrm{f}}=-63.5 \mathrm{~m} / \mathrm{s}$

What is friction ?

Friction can be characterized as a drive that stands up to the relative movement of two objects when there surface comes in contact. Friction gives traction that's required to walk without slipping. Friction is supportive in most cases. In any case, they moreover offer a incredible degree of restriction to the movement. In addition, almost 20 per cent of the motor control of automobiles is expended in overcoming frictional strengths within the moving parts.

The  four types of friction are:

1. Static friction
2. Sliding friction
3. Rolling friction
4. Fluid friction

To learn more about friction, visit;

brainly.com/question/24186853

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