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2 years ago

What are the benefits and limitations to using heating curves to studying phase

Physics

1 answer:

slega [8]2 years ago

4 0

Heating curves display how the temperature varies during heating.

What happens to a heating curve during a phase change?

Heating curves display how the temperature varies during heating. Curves that cool are the reverse.
They demonstrate how a substance cools down and how that affects the temperature. In the same way that heating curves feature horizontal flat areas when the state goes from gas to liquid or from liquid to solid, cooling curves also have those locations.
The temperature of a given volume of water changes as heat is added at a consistent pace, as shown by the water heating curve.
The temperature of the water does not vary throughout a phase shift, creating a plateau on the graph.

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A light bulb is rated at 25 W when operated at 120 V. How much charge enters (and leaves) the light bulb in 1. 0 min?

aleksklad [387]

The amount of charge enters (and leaves) is 12 Coulomb.

<h3 /><h3>How can we find the value of the amount of charge enters (and leaves)?</h3>

Here we are using the formula,

$I=\frac{P}{V}$ and $Q= I \times t$

We are given,

P = Power of the light bulb = 25 Watt.

V = The amount of voltage where the light bulb operated = 120 Volt.

t= The time when charge enters (and leaves) the light bulb = 1.0 min = $(1 \times 60) second$ = 60 S

We have to find,

I= The amount of current flows in the light bulb.

Q= The amount of charge enters (and leaves) the light bulb.

Now we substitute the values of known parameters in the first equation, we find that,

$I=\frac{P}{V}=\frac{25}{120}$

Or, $I= 0.20 A$

The amount of current flows in the light bulb is 0.20 Ampere.

Now, we put the value of I in the second equation,

$Q= I \times t= 0.20 \times 60$

Or, $Q=12 C$

So, from the above calculations we can see that the amount of charge enters (and leaves) the light bulb is 12 Coulomb.

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3 0

2 years ago

Will Mark BRAINLIEST!!!!!!!!!!!!!!!!!!!

vazorg [7]

r = distance of each mass in each hand from center = 0.6 m

m = mass of each mass in each hand = 2 kg

v = linear speed = 1.1 m/s

L = combined angular momentum of the masses = ?

Combined angular momentum of the masses is given as

L = 2 m v r

L = 2 (2) (1.1) (0.6)

L = 2.64 kg m²/s

v' = linear speed when she pulls her arms = ?

r' = distance of each mass from center after she pulls her arms = 0.15 m

Using conservation of momentum , angular momentum remains same, hence

L = 2 m v' r'

2.64 = 2 (2) (0.15) v'

v' = 4.4 m/s

4 0

4 years ago

Please help me fr fr !

Furkat [3]

The answer is A because it describes both toy cars

6 0

3 years ago

Kraig pulls a box to the right at an angle of 40 degrees to the horizontal with a force of 30 Newtons. If Kraig pulls the box a

eimsori [14]

Answer:

459.6J

Explanation:

Given parameters:

Angle of pull = 40°

Force applied = 30N

Distance moved = 20m

Unknown:

Work done by Kraig = ?

Solution:

To solve this problem;

Work done = F x dcosФ

d is the distance

F is the force

Ф is the angle given

Work done = 30 x 20cos40° = 459.6J

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3 years ago

The hottest stars are _____. -Blue -Orange -White -Red

AnnyKZ [126]

Answer:

yellow

Explanation:

6 0

4 years ago

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