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notka56 [123]
3 years ago
15

An escalator is 17.4 m long. If a person stands on the escalator, it takes 47.6 s to ride from the bottom to the top. If a perso

n walks up the moving escalator with a speed of 0.541 m/s relative to the escalator, how long does it take the person to get to the top?
Physics
1 answer:
lisov135 [29]3 years ago
3 0

Answer:

19.1 secs

Explanation:

The first step is to calculate the velocity

= 17.4/47.6

= 0.37 m/s

Therefore the time taken for the person to reach the top can be calculated as follows

= 17.4/(0.37+0.541)

= 17.4 / 0.911

= 19.1 secs

Hence the time taken is 19.1 secs

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A circuit has a 10 Ω resistor connected to a 1.5 V dry cell. What is the current that can flow in the circuit?
ludmilkaskok [199]

Here is the highly detailed, arcane, complex, technical form of Ohm's Law that is needed in order to answer this question  ===>  I = V / R  .

Current = (voltage) / (resistance)

Current = (1.5 V) / (10 Ω)

<em>Current = 0.15 Ampere</em>

8 0
2 years ago
Question 15 of 15
castortr0y [4]

Answer:

a and b

Explanation:

are the correct answers

7 0
3 years ago
A person's _____________ will change if they move from the Earth to the moon.
Diano4ka-milaya [45]

1. A person's weight will change if they move from the Earth to the moon.

In fact, the weight of a person is given by:

W=mg

where m is the mass of the person and g is the gravitational acceleration. The mass of the person, m, is the same on the Earth and on the moon, but the value of g is different on the Moon (about 1/6 of the Earth's value), so the weight also changes.


2. An astronaut is launched into space. The mass of the astronaut did not change. This is measured in Kg.

The mass of an object (or of a person, as in this case) is an intrinsec property of the object, that depends on the amount of matter inside the object: therefore, this quantity does not depend on the location of the object, so it is the same on the Earth, on the Moon and in space.


3. What is the weight of a ring tailed lemur that has a mass of 10 kg? -98 N

The weight of the lemur is given by:

W=mg

where m=10 kg is the lemur's mass and g=-9.8 m/s^2 is the gravitational acceleration. Using these numbers, we find

W=(10 kg)(-9.8 m/s^2)=-98 N

and the negative sign simply means that the direction of the weight is downward.


4. What is the mass of the lemur from the previous question if it was on the International Space Station? 10 kg

As we said in question 1), the mass of an object does not depend on the location, so the mass of the lemur is still 10 kg, as in the previous exercise.


5. A rocket being thrust upward as the force of the fuel being burned pushes downward is an example of which of Newton's laws? Third's Newton Law

Third's Newton Law states that:

"When an object A exerts a force on an object B, then object B exerts an equal and opposite force on object A".

Applied to this case, the two objects are the fuel and the rocket. The fuel is pushed backward by the rocket, so the fuel exerts an equal and opposite force on the rocket, which then moves forward.


6. When a cannon is fired, the projectile moves forward. According to Newton's 3rd law, the cannon will want to travel backward.

Third's Newton Law states that:

"When an object A exerts a force on an object B, then object B exerts an equal and opposite force on object A".

Applied to this case, the two objects are the cannon and the projectile.The projectile is pushed forward by the cannon, so the projectile exerts an equal and opposite force on the cannon, which moves backward.


7. An object has a weight of 21,532 N on Earth. What is the mass of the object? 2,197 kg

The weight of the object is given by: W=mg

If we re-arrange the formula and we use W=21,532 N, we can find the mass of the object:

m=\frac{W}{g}=\frac{21,532 N}{9.8 m/s^2}=2,197 kg


8. What is the mass of the object from the previous question if we put it on the moon? The force of gravity on the moon is 1.62 m/s2.  2,197 kg

As we said in question 4), the mass of an object does not change if we move it to another location, so its mass is still 2,197 kg.


9. How much force is exerted if a 250 kg object has an acceleration of 750 m/s2 ? 187,500 N

The force exerted on the object is given by Newton's second law:

F=ma

where F is the force, m=250 kg is the mass and a=750 m/s^2 is the acceleration. By using these numbers, we find

F=(250 kg)(750 m/s^2)=187,500 N


10. A resting soccer ball moving after it is kicked is an example of which of Newton's laws? Newton's second law

Newton's second law states that when an object is acted upon unbalanced force, the object has an acceleration, given by the law

F=ma

So, in this case, the ball is kicked and so an unbalanced force is applied to it, and for this reason the ball has an acceleration (in fact, it starts from rest, but then its velocity increases since it starts moving).

5 0
3 years ago
Calcula la energía cinética de un coche de 500kg de masa que se mueve a la velocidad de 100 km/h. Pasamos la velocidad a las uni
castortr0y [4]

Responder:

192,900.64 Julios

Explicación:

La energía cinética es la energía que posee un cuerpo en virtud de su movimiento. Sea la masa del cuerpo m, su velocidad v.

Energía cinética = 1/2 mv²

Parámetros dados

masa del coche = 500 kg

velocidad = 100 km / h

La velocidad debe estar en m / s según la unidad internacional estándar. Al convertir;

100 km / h = 100 * 1000/3600 m / s

100 km / h = 27,8 m / s

velocidad del cuerpo = 27,8 m / s

Necesario

Energía cinética del coche = 1/2 * 500 * 27,8²

Energía cinética del automóvil = 1/2 * 500 * 771.6

Energía cinética del automóvil = 1/2 * 385,801.28

Energía cinética del automóvil = 192,900.64 Julios

<em>Por lo tanto, la energía cinética del automóvil es 192,900.64 julios.</em>

5 0
3 years ago
A rms voltage of 120v produces a maximum current of 2.1a in a certain resistor. Find the resistance of the resistor. What is the
amid [387]

the resistance is 80.8Ω and average power 178.2 W

a) the value of resistance is given as,

R=rms voltage / rms current

and rms current = 2.1/√2

= I°/√2

rms current = 2.1/√2

rms current = 1.48

therefore R = 120/1.48

=80.4Ω

b) average power is product of rms current and rms voltage

P=120× 1.48

=178.2 W

learn more about power and current here:

brainly.com/question/19723198

#SPJ4

8 0
2 years ago
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