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Elena L [17]
3 years ago
12

A dielectric material is inserted between the charged plates of a parallel-plate capacitor. Do the following quantities increase

, decrease, or remain the same as equilibrium is reestablished?
1. Charge on plates (plates remain connected to battery)
2. Electric potential energy (plates isolated from battery before inserting dielectric)
3.Capacitance (plates isolated from battery before inserting dielectric)
4. Voltage between plates (plates remain connected to battery)
5. Charge on plates (plates isolated from battery before inserting dielectric)
6. Capacitance (plates remain connected to battery)
7. Electric potential energy (plates remain connected to battery)
8. Voltage between plates (plates isolated from battery before inserting dielectric)
Physics
2 answers:
sleet_krkn [62]3 years ago
7 0

Answer:

1. increase

2. remain the same

3. increases

4. decreases

5. remain the same

6. increases

7. decreases

8. remain the same

Explanation:

a. the formula for the capacitance of a capacitor relating the capacitor and the dielectric material is express as

C=e_oA/d........equation 1

also the capacitance and the charge is related as

Q=CV.......equation 2

from equation 1 as the dielectric material is introduced, the capacitance increases, the charge also increases

2. from the equation as the dielectric material is introduced, the capacitance increases, the electric potential also remain the same

3. from

C=e_oA/d........equation 1

we conclude that the capacitance increases

4. the voltage between the plates decreases

5. the charge remain the same because capacitance is constant

6. the capacitance increases

7. the electric potential decreases

8. remain the same

Arisa [49]3 years ago
6 0

Answer 1: the charge on the plates will increase

Explanation: placing a dielectric between two charged plate increases its capacitance

C = Q/V,

If the plates remain connected then the voltage remains the same.

Therefore for an increase in capacitance charge will increase.

Answer 2: electric field potential remains the same.

Explanation: if the plates are disconnected, charge on plates remains contant while voltage varies with change in distance, electric field intensity remains constant and this is proportional to the electric potential energy.

Answer 3: capacitance increases

Explanation: introducing a dielectric between two plates causes opposite charges to be induced on the faces of the dielectric. This also reduces the p.d across the capacitor.

Answer 4: voltage remains constant.

Explanation: A connected plate has a constant voltage across its field.

Answer 5: charge remains contant.

Explanation: capacitance will increase with introduction of dielectric, p.d across the plates will drop, the charge will remain constant.

Answer 6: capacitance increases

Explanation: placing a dielectric between plates always increase the capacitance.

Answer 7: electric potential energy falls.

Answer 8: voltage between plates decreases

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Lilit [14]

Answer:

Accuracy

Explanation:

I think accuracy is more important. When it comes to vital organs in the body, the exactness of getting the measurement is paramount. Accuracy deals with getting very close, almost exact you may say, to a known standard. Precision on the other hand, deals with how easy a measurement can be retaken, reproduced or remade, irrespective of how far or close they are from the accepted norm.

From this, we can agree that precision neglects the most important factor, closeness or say, exactness. Precision isn't bothered by it. And while that can be excused in a few instances, it certainly can not be permitted when it comes to life, or organs of the body

7 0
3 years ago
You do 45.0 joules of work and 3.00 seconds how much power do you use​
Arada [10]

Answer:

15 watt

Explanation:

Power is the rate at which work is done.

This means you divide the work done with the amount of time used to perform the work.

The formula for Power is : P = W/t  where;

W= work done in J = 45

t= time in seconds = 3 sec

P= 45/ 3 = 15 watt

8 0
3 years ago
I'll mark brainliest
irga5000 [103]

Answer:

A) 35 ft

B) 5 ft

C) Net displacement = distance covered by the dog to retrieve the stick - distance covered before the dog starts chewing the stick

Explanation:

A) Total distance covered by the dog = 20 + 15

                                  = 35 ft

B) Since the other distance covered by the dog before chewing the stick, after the retrieval, was in an opposite direction to the initial direction, then;

total displacement of the dog = 20 - 15

                                  = 5 ft

C) Net displacement = distance covered by the dog to retrieve the stick + distance covered before the dog starts chewing the stick

But, displacement involves a specified direction. The distance covered before the dog starts chewing the stick was in an opposite direction to the initial direction.

Thus,

Net displacement = distance covered by the dog to retrieve the stick - distance covered before the dog starts chewing the stick

7 0
3 years ago
How fast is a wave traveling if it has a wavelength of 7 meters and a frequency of 11 Hz?
pashok25 [27]

Answer:

\huge{ \boxed{ \bold{ \sf{77 \: m/s}}}}

☯ Question :

  • How fast is a wave travelling if it has a wavelength of 7 meters and a frequency of 11 Hz?

☯ \underbrace{ \sf{Required \: Answer  :  }}

☥ Given :

  • Wavelength ( λ ) = 7 meters
  • Frequency ( f ) = 11 Hz

☥ To find :

  • Speed of sound ( v ) = ?

☄ We know ,

\boxed{ \sf{v = f \times λ}}

where ,

  • v = speed of sound
  • f = frequency
  • λ = wavelength

Now, substitute the values and solve for v.

➺ \sf{v = 11 \times 7}

➺ \boxed{ \sf{v = 77 \: m/s}}

-------------------------------------------------------------------

✑ Additional Info :

  • Frequency : The number of complete vibrations made by a particle of a body in one second is called it's frequency. It is denoted by the letter f . The SI unit of frequency is hertz ( Hz ).

  • Wavelength : The distance between two consecutive compressions or rarefactions of a sound wave is called wavelength of that wave. It is denoted by λ ( lambda ) and it's SI unit is m.

  • Speed of a sound wave : The distance covered by a sound wave in one second is called speed of sound wave. It depends on the product of wavelength and frequency of the wave.

Hope I helped!

Have a wonderful time! ツ

▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁

7 0
3 years ago
This problem follows up on a discussion from lecture. A wind turbine with an efficiency of 45% for converting wind energy into e
Volgvan

Answer:

4.1 m

Explanation:

10 kW = 10000 W

20mi/h = 20*1.6 km/mi = 32 km/h = 32 * 1000 (m/km) *(1/3600) hr/s = 8.89 m/s

The power yielded by the wind turbine can be calculated using the following formula

P = \frac{1}{2} \rho v^3 A C_p

where \rho = 1.2 kg/m^3 is the air density, v = 8.89 m/s is the wind speed, A is the swept area and C_p = 0.45 is the efficiency

10000 = 0.5 * 1.2 * 8.89^3 * A * 0.45

10000 = 190A

A = 10000 / 190 = 52.7 m^2

The swept area is a circle with radius r being the blade length

\pi r^2 = A = 52.7

r^2 = 52.7 / \pi = 16.79

r = \sqrt{16.79} = 4.1 m

4 0
3 years ago
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