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svp [43]
3 years ago
12

A fire hose held near the ground shoots water at a speed of 6.5 m/s. At what angle(s) should the nozzle point in order that the

water land 2.5m away?
Physics
1 answer:
valina [46]3 years ago
8 0
The speed of water can be split into vertical and horizontal speed components:
v_x = 6.5 cos \theta \\ v_y = 6.5 sin \theta

Due to the force of gravity, the y component will be parabolic. The x component will be linear:
y(t) = -4.9t^2 + (6.5sin \theta) t \\  \\ x(t) = (6.5 cos \theta) t
To find when the water hits the ground 2.5m away, set y= 0 and x = 2.5
-4.9t^2 + (6.5sin \theta) t=0 \\  \\ t = \frac{6.5}{4.9} sin \theta \\ \\(6.5 cos \theta)(\frac{6.5}{4.9} sin \theta) = 2.5 \\  \\ sin \theta cos \theta = 0.29 \\  \\ sin 2\theta = 0.58 \\  \\ 2\theta = 35.4, 144.6 \\  \\ \theta = 17.7,72.3
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