Bottom left.
It has a point that is the farthest from the rest of the points. That point is an outlier.
Hello from MrBillDoesMath!
Answer:
All equations have two real roots.
Discussion:
The solutions of the quadratic ax^2 + bx + c = 0 are given by the formula:
x = (-b +\- sqrt(b^2-4ac) ) / (2a)
The key element is the discriminant, D, which equals (b^2-4ac)
For 2) a = 3, b = 4, c = -4, D = 4^2 - 4(3)(-4) = 16 + 48 = 64 > 0 so there are two real solutions
For 4) D = b^2 - 4ac = (-1)^2 - 4(6)(-1) = 1 + 24 = 25 >0 so there are two real solutions
For 6), a = -3, b = 12, c= -11, D = 12^2 - 4(-3)(-11) = 144 - 132 = 12 > 0 so
there are two real solutions
Thank you,
MrB
Answer:
Step-by-step explanation:
I believe you have to make the -x to a positive by dividing because there is still an invisible one there, like:
-x/-1 < -6/-1
x > 6 . and switch the sign since you're dividing by a negative : )
Answer:
(a) This is just `8` people being arranged in a row: `8! = 40,320` (b) Regard the `2` boys as one "unit" and so there are `7` "units" to arrange. This can be done `7! = 5040` ways. The boys can be arranged in `2! = 2` ways, so the required answer is `7! × 2! = 10,080` (c) There are only `2` possibilities: the boys are together or they are not.
Step-by-step explanation:
That is a virus do not go to it