Find the constant of variation for the quadratic variation of 9y=4x^2
1 answer:
You might be interested in
Answer: The value of y is 39.6 when x = 11 and the required expression is y(11) = 39.6
Step-by-step explanation:
Since we have given that
y varies directly as x.
If y = 18, when x = 5.
So, we need to find the value of y when x is 11.
According to question, we get that
Hence, the value of y is 39.6 when x = 11 and the required expression is y(11) = 39.6