Answer
a) charge of the sodium ion is,
q = n e
q = 2.68 x 10¹⁶ x 1.6 x 10⁻¹⁹
q = 4.288 x 10⁻³ C
charge of the chlorine ion is,
q' = n e
q' = 3.92 x 10¹⁶ x 1.6 x 10⁻¹⁹
q' = 6.272 x 10⁻³ C
the current



b) positive ion moves toward negative electrode hence direction of will be in the direction toward negative electrode.
The radius R of the turn is 1.984 km.
<u>Explanation:</u>
As the falcon is experiencing a centripetal motion, the acceleration exhibited by the falcon will be centripetal acceleration. The formula for centripetal acceleration is

Here a is the acceleration for centripetal motion, v is the velocity and R is the radius of the circular path.
As the centripetal acceleration is given as 0.6 g, the velocity is given as 108 m/s, then the radius of the path can be determined as


So, the radius of the turn is 1.984 km.
<span> In radioactive decay, an unstable atomic nucleus emits particles or radiation and converts to a different atomic nucleus. If the new nucleus is unstable, it will decay again, until eventually, a stable nucleus is formed. Such a sequence of nuclear decays forms a decay series.
The half-life of a radioactive substance is the time required for half of the atoms of a radioactive isotope to decay. If you have, say, 1 million atoms of a specific isotope in a sample, the time required for 500,000 of those atoms to decay is the half-life of that specific isotope. If you have 50 atoms of that isotope, 25 atoms will decay in the same amount of time.
Because the half-life is fixed for a specific isotope, it can be used to date objects. You compare the decay rate of an old object with the decay rate of a fresh sample. Nuclear decay is a first-order process and can be described by a specific mathematical equation, which depends on the decay rate and the half-life. Knowing those values, you can work back and determine the age of an object, as compared with a standard sample. Old objects will not have as much of a radioactive isotope in them as new objects, since the isotopes will have decayed over time in the old object.</span>