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1 year ago

What is the equation of the line that passes through the point (5, 1) and has a slope of 1/5 ?

Mathematics

1 answer:

OverLord2011 [107]1 year ago

5 0

Answer: $y=\frac{1}{5}x$

Step-by-step explanation:

$y-1=\frac{1}{5}(x-5)\\\\y-1=\frac{1}{5}x-1\\\\y=\frac{1}{5}x$

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Option D:

$\left(y^{2}+3 y+7\right)\left(8 y^{2}+y+1\right)=8 y^{4}+25 y^{3}+60 y^{2}+10y+7$

Solution:

Given expression is $\left(y^{2}+3 y+7\right)\left(8 y^{2}+y+1\right)$ .

<u>To find the product of the expression:</u>

$\left(y^{2}+3 y+7\right)\left(8 y^{2}+y+1\right)$

Multiply each term of the first term with each term of the 2nd term.

$=y^{2}\left(8 y^{2}+y+1\right) +3 y\left(8 y^{2}+y+1\right) +7\left(8 y^{2}+y+1\right)$

Using the exponent rule: $a^m \cdot a^n = a^{m+n}$

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Step-by-step explanation:

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