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Gelneren [198K]
3 years ago
15

Find the value of the variable.

Mathematics
1 answer:
Nikolay [14]3 years ago
4 0

we are given that

both sides are equal

so, their length must be equal

HK=\sqrt{(p-1)^2+(5-2)^2}

HK=\sqrt{(p-1)^2+9}

now, we can find other side

JK=\sqrt{(p-7)^2+(5-2)^2}

JK=\sqrt{(p-7)^2+9}

now, we can set them equal

HK=JK

\sqrt{(p-1)^2+9}=\sqrt{(p-7)^2+9}

now, we can take square both sides

(p-1)^2+9=(p-7)^2+9

now, we can solve for p

(p-1)^2=(p-7)^2

p^2-2p+1=p^2-14p+49

-2p+1=-14p+49

12p=48

p=4..............Answer

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Given: △ABC, AB=5 sqrt 2 m∠A=45°, m∠C=30° Find: BC and AC will give brainliest!!! By the way the answer is not 5 and 3.66
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Answer:

Therefore,

BC=a=10\ units\\\\AC=b=13.66\ units

Step-by-step explanation:

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Solution:

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In Δ ABC,

\frac{a}{\sin A}= \frac{b}{\sin B}= \frac{c}{\sin C}

substituting the given values we get

\frac{a}{\sin 45}= \frac{b}{\sin 105}= \frac{5\sqrt{2} }{\sin 30}

∴ \frac{a}{\sin 45}= \frac{5\sqrt{2} }{\sin 30}\\\\a=\sin 45\times \frac{5\sqrt{2} }{\sin 30}\\\\a=\frac{1}{\sqrt{2} }\times \frac{5\sqrt{2} }{0.5} \\\\\\a=\frac{5}{0.5} =10\\\therefore BC = a = 10\ units

Similarly for 'b',

\frac{b}{\sin 105}= \frac{5\sqrt{2} }{\sin 30}\\\frac{b}{0.9659}= \frac{5\sqrt{2} }{0.5}\\\\b=0.9659\times \frac{5\sqrt{2} }{0.5}\\\\b=\frac{6.8301}{0.5} \\\\b=13.66\\\therefore AC = b =13.66\ units\\

Therefore,

BC=a=10\ units\\\\AC=b=13.66\ units

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