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ella [17]
3 years ago
12

What is the pH of a solution with [OH-] = 5.40 x 10-3 M?

Chemistry
1 answer:
igomit [66]3 years ago
7 0
pH: 5.4E-3
pOH: 13.9946
[H+]: 0.987643022777
[OH-]: 1.01251158256E-14 acid
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A buffer is prepared by adding 150mL of 0.50 M NH3 to 250mL of 0.50 M NH4NO3. What is the pH of the final solution? (Kb for NH3
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From the calculations, the pH of the final solution is 9.04.

<h3>What is the pH of the buffer?</h3>

We can use the Henderson Hasselbach equation to obtain the final pH of the solution in terms of the pKb and the base concentration.

Number of moles of salt = 250/1000 L * 0.5 M = 0.125 moles

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Total volume of solution = 250ml + 150ml = 400ml or 0.4 L

Molarity of base = 0.075 moles/ 0.4 L = 0.1875 M

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pOH = 4.74 + log[0.3125/0.1875 ]

pOH = 4.96

pH = 14- 4.96

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Learn more about pH:brainly.com/question/15289741

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