Answer:
The pressure will be 0.4 atm.
Explanation:
The gas laws are a set of chemical and physical laws that allow determining the behavior of gases in a closed system. The parameters evaluated in these laws are pressure, volume, temperature and moles.
As the volume increases, the gas particles (atoms or molecules) take longer to reach the walls of the container and therefore collide with them less times per unit of time. This means that the pressure will be lower because it represents the frequency of collisions of the gas against the walls. In this way pressure and volume are related, determining Boyle's law which says:
"The volume occupied by a certain gaseous mass at constant temperature is inversely proportional to pressure"
Boyle's law is expressed mathematically as:
P*V= k
If you initially have the gas at a volume V1 and press P1, when the conditions change to a volume V2 and pressure P2, the following is satisfied:
P1*V1= P2*V2
In this case:
- P1= 1.2 atm
- V1= 4 L
- P2= ?
- V2= 12 L
Replacing:
1.2 atm* 4 L= P2* 12 L
Solving:
P2= 0.4 atm
<u><em>The pressure will be 0.4 atm.</em></u>
The formula for the change in Gibbs energy of a solid is:
ΔG = Vm ΔP
where, ΔG is change in Gibbs, Vm is molar volume, ΔP is
change in pressure
ΔP = P(final) – P(initial)
P(final) = 1 atm = 101325 Pa
P(initial) = ρ_water *g *h = (1030 kg/m^3) * 9.8 m/s^2 *
2000 m = 20188000 kg m/s^2 = 20188000 Pa
Vm = (950 kg/m^3) * (1000 mol / 891.48 kg) = 1065.64
mol/m^3
So,
ΔG = (1065.64 mol/m^3) * (101325 Pa - 20188000 Pa)
<span>ΔG = -21405164347 J = -21.4 GJ</span>
Answer:
The volume is 13, 69 L
Explanation:
We use the formula PV=nRT. We convert the temperature in Celsius into Kelvin and the pressure in mmHg into atm.
0°C= 273K---> 56°C= 56 + 273= 329K
760 mmHg----1 atm
719 mmHg----x= (719 mmHgx 1 atm)/760 mmHg= 0,95 atm
PV=nRT ---> V= (nRT)/P
V=( 0,482 molx 0,082 l atm/K mol x 329K)/0,95 atm
<em>V=13,68778526 L</em>
Answer:
142.82 g
Explanation:
The following data were obtained from the question:
Volume of water = 12 mL
Volume of water + gold = 19.4 mL
Density of gol= 19.3 g/cm³
Mass of gold =.?
Next, we shall determine the volume of the gold. This can be obtained as follow:
Volume of water = 12 mL
Volume of water + gold = 19.4 mL
Volume of gold =.?
Volume of gold = (Volume of water + gold) – (Volume of water)
Volume of gold = 19.4 – 12
Volume of gold = 7.4 mL
Finally, we shall determine the mass of the gold as follow:
Note: 1 mL is equivalent to 1 cm³
Volume of gold = 7.4 mL
Density of gol= 19.3 g/cm³ = 19.3 g/mL
Mass of gold =?
Density = mass /volume
19.3 = mass of gold /7.4
Cross multiply
Mass of gold = 19.3 × 7.4
Mass of gold = 142.82 g
Therefore, the mass of the gold pebble is 142.82 g
