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JulsSmile [24]
2 years ago
15

Why must the test charge used to determine the electric field be very, very small?.

Physics
1 answer:
vekshin12 years ago
8 0

The test charge used to determine the electric field is very, very small so that its presence does not affect the electrical field because of the supply price. The electrical rate that produces the electric area is known as a source charge.

An electric-powered area is a physical area that surrounds electrically charged debris and exerts pressure on all differently charged particles inside the area, both attracting or repelling them. It also refers back to the physical field for a machine of charged particles.

Electric-powered discipline is described as the electrical force in keeping with unit fee. The path of the sector is taken to be the route of the force it might exert on a fine check price. the electric discipline is radially outward from a nice rate and radially in toward a bad point rate.

An electric discipline is a vicinity of space around an electrically charged particle or object in which an electric charge might sense force. An electric field is a vector amount and may be visualized as arrows going in the direction of or away from fees.

Learn more about  electric here brainly.com/question/24317284

#SPJ4

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A pendulum is raised to a height of 0.3m above its lowest point and released. What is the velocity of the pendulum at its lowest
enyata [817]

Answer:

v = 2,425 m / s

Explanation:

A simple pendulum has anergy stored at the highest point of the path and this energy is conserved throughout the movement.

highest point

           Em₀ = U = m g y

lowest point

          Em_{f} = K = ½ m v²

         Em₀ = Em_{f}

        mg y = ½ m v²

        v = √ 2gy

let's calculate

        v = √ (2 9.8 0.3)

        v = 2,425 m / s

3 0
3 years ago
What happens to the density of ocean water when salinity increases? A. It increases. B. It decreases. C. It becomes variable. D.
omeli [17]
A. It increases... but slightly. Good luck!
3 0
3 years ago
A draft is made of a plastic block with a density of 650kg/m^3, and its dimensions are 2.0mx3.0mx5.0m ,what is the raft's appare
mixas84 [53]
Weight in water = mass of block - mass of volume of displaced water
8 0
3 years ago
Help in solving this question please<br>(question is on the picture )<br>​
MakcuM [25]

Answer:

Jesus

Explanation:

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6 0
2 years ago
A gazelle leaps from a cliff 2.5 m high with a speed of 5.6m/s.
jeyben [28]

Initial speed of Gazelle is along x direction and its value will be

v_x = 5.6 m/s

also its initial height is given as

y = 2.5 m

Part a)

now from kinematics along Y direction

\Delta y = v_y t + \frac{1}{2} at^2

as we know that

\Delta y = 0

v_y = 0

a = 9.8 m/s^2

2.5 = 0 + \frac{1}{2} (9.8) t^2

t = 0.714 s

Part b)

distance moved horizontally

\Delta x = v_x t

as we know that

v_x = 5.6 m/s

now we will have

v_x = 5.6 (0.714) = 4m

so it will lend at distance of 4 m.

Part c)

final velocity in vertical direction

v_{fy} = v_y + at

v_{fy} = 0 + (9.8)(0.714) = 7 m/s

v_x = 5.6 m/s

so net speed will be

v^2 = v_x^2 + v_y^2

v^2 = 7^2 + 5.6^2

v = 8.96 m/s


7 0
3 years ago
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