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3 years ago

The rotation period for Venus is___days. (pls help!) 365 186 512 243

Physics

2 answers:

sattari [20]3 years ago

6 0

Answer:

243 days

Explanation:

hjlf3 years ago

5 0

Answer:

243

Explanation:

Most planets also rotate on their axes in an anti-clockwise direction, but Venus rotates clockwise in retrograde rotation once every 243 Earth days—the slowest rotation of any planet. Because its rotation is so slow, Venus is very close to spherical.

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People under going physical therapy after an injury often find it helpful to perform exercise in water? Why?

BARSIC [14]

Because water puts less weight on the joints helping prevent more pain and potentially problems

Also if you could give me Brainily that would be amazing

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3 years ago

Three cars, car x, car y, and car z, begin accelerating from rest, at the same time. car x is more massive than car y, which is

grigory [225]

When the net force exerted on each car is identical. after 10 seconds, the amount of momentum is same for all cars.

<h3>What is impulse?</h3>

The change in momentum is equal to the product of impact force applied while colliding and time for that impact.

F. t = m (Vf -Vi)

where, Vf is the final velocity and Vi is the initial velocity.

For car X, Fx x t = Mx Vx

For car Y, Fy x t = My Vy

For car Z, Fz x t = Mz Vz

The force applied is same for all and the the time is also same equal to 10 seconds. The impulse is same for all the cars.

Thus, the three cars have same momentum.

Learn more about impulse.

brainly.com/question/16980676

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2 years ago

What will be the ratio of distances between the two charges of each pair of charges (1µC, 2µC) and (2µC, -3uC) so that force her

Alenkinab [10]

Answer: Anurag Mishra - Problems in Physics - Electricity and Magnetism ... Between two infinitely long wires having linear charge densities}. and -].·there are two points A ... the ratio of the electric force between them to t:-:c grav:tadonal force between them? (a) 10 8 ... d between the first two charges on the straight line at a distance

Explanation:

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4 0

3 years ago

A car is traveling at 50 mi/h when the brakes are fully applied, producing a constant deceleration of 38 ft/s2. what is the dist

e-lub [12.9K]

Convert 38 ft/s^2 to mi/h^2. Then we se the conversion factor > 1 mile = 5280 feet and 1 hour = 3600 seconds.

So now we show it > $38 \frac{ft}{s^2} x \frac{1mi}{5280ft} x \frac{(3600s)^2}{(1h)^2} = 93272.27 \frac{mi}{h^2}$

Then we have to use the formula of constant acceleration to determine the distance traveled by the car before it ended up stopping.

Which the formula for constant acceleration would be > $v_2^2=v_1^2 + 2as$

The initial velocity is 50mi/h $(v_1=50)$

When it stops the final velocity is $(v_2=0)$

Since the given is deceleration it means the number we had gotten earlier would be a negative so a = -93272.27

Then we substitute the values in....

$0^2 = 50^2 + 2(-93272.27)s

0 = 2500 - 186544.54s

Isolate S next.

185644.54s= 2500

s = 2500/(185644.54)

s=0.0134
$

So we can say the car stopped at 0.0134 miles before it came to a stop but to express the distance traveled in feet we need to use the conversion factor of 1 mile = 5280 feet in otherwards > $0.0134 mi * \frac{5280ft}{1mi} = 70.8 ft$
So this means that the car traveled in feet 70.8 ft before it came to a stop.

4 0

3 years ago

A physics professor is pushed up a ramp inclined upward at 30.0° above the horizontal as she sits in her desk chair, which slide

11111nata11111 [884]

Answer:

V = 3.17 m/s

Explanation:

Given

Mass of the professor m = 85.0 kg

Angle of the ramp θ = 30.0°

Length travelled L = 2.50 m

Force applied F = 600 N

Initial Speed u = 2.00 m/s

Solution

Work = Change in kinetic energy

$F_{net}d = \frac{1}{2}mv^{2} - \frac{1}{2}mu^{2}\\\frac{2F_{net}d }{m} = v^{2} -u^{2}\\ v^{2} =\frac{2F_{net}d }{m} +u^{2}\\ v^{2} =\frac{2(600cos30 - 85\times 9.8 \times sin30) \times 2.5 }{85} +2.00^{2}\\ v^{2} = 10.066\\v = 3..17m/s$

7 0

3 years ago