Answer:
- 6.48 J K⁻¹
Explanation:
Temperature of gas = 20°C
= 273 +20 = 293 K.
As temperature is fixed , there will be no change in gas internal energy
Δ E = 0
From the relation
Δ Q = Δ E+ Δ W
Work done on the gas is 1.9 x 10³
Δ W = - 1.9 x 10³ J
Δ Q = - 1.9 x 10³ J
Δ S = Δ Q / T
=
= - 6.48 J K⁻¹
6. D
7. D
8. B
let me know if you need clarification
Newton told him the orbits must have ellipses. Let me know if this helps.
Answer:
The potential at a distance of 0.9 m is 266.67 V.
Explanation:
Charge = Q
Potential is 400 V at a distance 0.6 m .
Let the potential is V at a distance 0.9 m.
Use the formula of potential.