Answer:
the number density of the protons in the beam is 3.2 × 10¹³ m⁻³
Explanation:
Given that;
diameter D = 2.0 mm
current I = 1.0 mA
K.E of each proton is 20 MeV
the number density of the protons in the beam = ?
Now, we make use of the relation between current and drift velocity
I = MeAv ⇒ 1 / eAv
The kinetic energy of protons is given by;
K = 
v²
v = √( 2K /
)
lets relate the cross-sectional area A of the beam to its diameter D;
A =
πD²
now, we substitute for v and A
n = I /
πeD² ×√( 2K /
)
n = 4I/π eD² × √(
/ 2K )
so we plug in our values;
n = ((4×1.0 mA)/(π(1.602×10⁻¹⁹C)(2mm)²) × √(1.673×10⁻²⁷kg / 2×( 20 MeV)(1.602×10⁻¹⁹ J/ev )
n = 1.98695 × 10¹⁸ × 1.6157967 × 10⁻⁵
n = 3.2 × 10¹³ m⁻³
Therefore, the number density of the protons in the beam is 3.2 × 10¹³ m⁻³
Answer: 43.58 min
Explanation:
Knowing the volume of a rectangular object is length x width x height, we have two volumes:


And we know it takes a time of 4 minutes to fill
.
If we want to know how long will it take the same hose to fill another tank with volume
, we can use the <u>Rule of three</u>, which is a mathematical rule to find out an amount that is with another quantity given in the same relation as other two also known:
---- 
---- 

Finally:

Answer:
28 miles
Explanation:
3,223 meters/day x 14 days = 45,122 meters
1 meter = 3.28 feet
45,122 meters = 148,000 feet
5280 feet = 1 mile
148,000 feet = 28 miles
If it is already on then maybe it is moving a lot faster than it was before.