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vagabundo [1.1K]
3 years ago
14

A boat sails along the shore. To an observer, the boat appears to move at a speed of 22 m/s, and a man on the boat walking forwa

rd appears to have a speed of 23.1 m/s. How long does it take the man to move 3 m relative to the boat?
Physics
1 answer:
seropon [69]3 years ago
7 0
The boat is moving at 22 m/s while the man is moving at 23.1 m/s.

That means the man, relative to the boat, is moving at 23.1-22 = 1.1 m/s.

v =d/t, so t = d/v --> t = 3/1.1 = 2.7 s
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Yes, his velocity will decrease the further he slides.
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Which is a correct example of the principle of conservation of momentum? A) reversing of a car at a dead end B) conversion of ra
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Light rays in a material with index of refrection 1.35 1.35 can undergo total internal reflection when they strike the interface
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Answer:

1.30

Explanation:

To calculate the critical angle we have ti use the formula:

sin\theta_c=\frac{n_2}{n_1}

where theta_c is the critical angle, n1 is the index of refraction of the material where the light is totally reflected, and n2 is the refractive index of the other material.

By taking n_2 and replacing we obtain:

n_2=n_1sin\theta_c=(1.35)sin75.1\°=1.30

hope this helps!!

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Which is an example of nuclear energy being converted into heat and light energy?
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A 0.02kg dart is loaded into a toy spring gun by compressing the spring 6cm. If the spring has a constant of 20 N/m, find… a. Th
katrin2010 [14]

Answer:

a) 0.036 J b) 0.036J c) 0.036 d) 1.9m/s e) 0.18 m

Explanation:

Mass of the dart = 0.02kg, the spring was compressed to 6cm

Work needed to compress the spring = 1/2*k*x ^2 where k is the force constant of the spring in N/m, x is the distance it was compressed in m

Work needed to compress the spring = 0.5 * 20* 0.06^2 since 6cm = 6 / 100 = 0.06 m

Work needed to compress the spring = 0.036J

b) the total energy stored in the spring = the work done to compress the spring = 0.036J

c) kinetic energy of the dart as it leaves the the spring = elastic potential energy stored in the spring = the work done in compressing the = 0.036J using the law of conservation of energy; energy is neither created nor destroyed but transformed from one form to another.

d) 1/2mv^2 = 0.036

mv^2 = 0.036*2

v^2 = 0.036*2 / 0.02 = 3.6

v = √3.6 = 1.897 approx 1.9m/s

e) kinetic energy of the dart = work done against gravity to get the body to height h

Work done against gravity = potential energy conserved at height = -mgh g is negative because the motion is upward while gravity acts downward

0.036 = 0.02 * 9.81 * h

0.036 / ( 0.02*9.81) = h

h = 0.18 m

6 0
3 years ago
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