Answer:
0-4 acceleration comes at 12 m/s where (B) stagnates at 12 m/s and remains for 4 seconds (C) is breaks being activated slowing the car to 6 m/s in 2 seconds and (D) over the course of 4 seconds brings the car to 10 m/s.
Explanation:
Answer:
15 m per second
900m per minute
54,000 per hour
Explanation:
60 divided by 4 to get per second then times 60 for per minutes
then times 60 to get per hour
Sound is produced when something <span>vibrates.
</span>
Answer:
a) 8.61 m/s, b) 5.73 m
Explanation:
a) During the collision, momentum is conserved.
mv = (m + M) V
(12.5 g) (86.4 m/s) = (12.5 g + 113 g) V
V = 8.61 m/s
b) After the collision, energy is conserved.
Kinetic energy = Work done by friction
1/2 (m + M) V² = F d
1/2 (m + M) V² = N μk d
1/2 (m + M) V² = (m + M) g μk d
1/2 V² = g μk d
d = V² / (2g μk)
d = (8.61 m/s)² / (2 × 9.8 m/s² × 0.659)
d = 5.73 m
Notice we used the kinetic coefficient of friction. That's the friction when an object is moving. The static coefficient of friction is the friction on a stationary object. Since the bullet/block combination is sliding across the surface, we use the kinetic coefficient.
What it looks to be that you found in A was the "initial"...b/c the question asks:
<span>"how much energy does the electron have 'initially' in the n=4 excited state?" </span>
<span>"final" would be where it 'finally' ends up at, ie. its last stop...as for this question...the 'ground state' as in its lowest energy level. </span>
The answer comes to: <span>−1.36×10^−19 J</span>
You use the same equation for the second part as for part a.
<span>just have to subract the 2 as in the only diff for part 2 is that you use 1squared rather than 4squared & subract "final -initial" & you should get -2.05*10^-18 as your answer. </span>
