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Helga [31]
3 years ago
10

What factors determine the amount of air resistance an object experiences?

Physics
1 answer:
geniusboy [140]3 years ago
3 0
The pressure of the air at the way its blowing

You might be interested in
Two different simple harmonic oscillators have the same natural frequency (f=8.80 Hz) when they are on the surface of the Earth.
bekas [8.4K]

Answer:

8.80 Hz

Explanation:

The frequency of a loaded spring is given by

f=\dfrac{1}{2\pi}\sqrt{\dfrac{k}{m}}

where k and m are the spring constant and the mass of the load respectively. The values of these do not change because they are internal properties of the components of the system.

Hence, the frequency of the vertical spring mass does not change and is 8.80 Hz.

On the other hand, the frequency of the simple pendulum is affected because it is given by

\dfrac{1}{2\pi}\sqrt{\dfrac{g}{l}}

where g and l are acceleration due to gravity and length of the pendulum, respectively. It is thus seen that it depends on g, which changes with location. In fact, the new frequency is given by

f_2 = 8.80\sqrt{\dfrac{1.67}{9.81}}=3.63 \text{ Hz}

3 0
3 years ago
How does the water cycle transport energy and matter
natali 33 [55]

Explanation:

Water evaporates from the surface of the earth and through the leaves of the plants and trees by absorbing the heat energy from the surrounding.

This water then converts into vapour and goes up into the atmosphere where the temperature is low in the troposphere and condenses to form the clouds. During the cloud formation the heat form the vapour is absorbed in the troposphere.

These clouds when get saturated then fall in the form of precipitation of water, snow etc. Replenishing back the water of the earth.

7 0
3 years ago
The position of a particle s given by x=3-2t+3t^2. What is its instantaneous velocity and instantaneous acceleration as t=3.
Leno4ka [110]

Explanation:

velocity = dx/dt

\frac{dx}{dt}  = 6t - 2 = 16

acceleration =

\frac{ {d}^{2}x }{d {t}^{2} }  = 6 \ \\

5 0
2 years ago
A proton orbits a long charged wire, making 1.80 ×106 revolutions per second. The radius of the orbit is 1.20 cm What is the wir
Fantom [35]

Answer:

linear charge density = -9.495 × 10^{-34} C/m

Explanation:

given data

revolutions per second = 1.80 × 10^{6}

radius = 1.20 cm

solution

we know that when proton to revolve around charge wire then centripetal force is require to be in orbit of radius around provide by electric force

so

- q × E = m × w² × r     ..................1

- 9 × 10^{9}  × \frac{2*linear\ charge\ density}r} q =  m × w² × r   ............2

and w = \frac{2*\pi}{T}  

w = \frac{d\theta }{dt}

w = 1.80 × 10^{6} × \frac{2*\pi}{1}

w = 11304000 rad/s

so here from equation 2

- 9 × 10^{9}  × \frac{2*linear\ charge\ density}{0.012} 1.80 × 10^{6} =  1.672 × 10^{-27} × 11304000² × 0.0120  

linear charge density = -9.495 × 10^{-34} C/m

8 0
3 years ago
Which of the following are true for acceleration?
Fittoniya [83]

The SI unit for acceleration is m/s2 ( D)

6 0
3 years ago
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