We don't know anything about Shoreville, or the coastline or shoreline
around it. So the only answer we can offer is the broad world-wide average.
Between consecutive appearances of the moon at the same place in the sky,
there are two high and two low tides.
The moon appears to circle the entire sky in 29.531 days, whereas the
sky itself, referred to the sun, circles in 24 hours. So the moon takes
(29.531 / 24) = 1.2305 days
to return to the same place in the sky.
That period of time is also the cycle of the four tide extremes ... 2 highs
and 2 lows. So the period between two extremes averages
(1.2305 / 4) = 0.3076 day = 7.38 hours = 7h 23min .
If one extreme tide occurs at 12:00, we would expect the next one at 7:23 .
Answer:
Explanation:
As we know that the runner starts from rest position
So here we can say
now the distance moved by the runner is given as
also we know that final speed of the runner will be
now we know that
The weight required to stretch the spring 12.5 cm is 7.5 N (Option A)
<h3>Data obtained from the question</h3>
- Initial weight (W₁) = 3 N
- Initial Length (L₁) = 5 cm
- New length (L₂) = 12.5 cm
- New Weight (W₂) =?
<h3>How to determine the new weight </h3>
The new weight required to stretch the spring can be obtained as follow:
W₁ / L₁ = W₂ / L₂
3 / 5 = W₂ / 12.5
Cross multiply
W₂ × 5 = 3 × 12.5
Divide both sides by 5
W₂ = (3 × 12.5) / 5
W₂ = 7.5 N
Learn more about spring constant:
brainly.com/question/9199238
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Answer:
5.8 m/s
Explanation:
Let v = velocity of bike relative to Betty = -12.0 m/s (since the bike is moving away from betty).
u = velocity of ball relative to bike = + 17.8 m/s
and V = velocity of ball relative to Betty.
So, by Galilean relativity,
V = v + u
V = -12.0 m/s + 17.8 m/s
V = 5.8 m/s
So, the velocity of the ball as measured by Betty is 5.8 m/s