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Aleksandr-060686 [28]
3 years ago
6

11. Which has the greater acceleration: a car that increases its speed from 50 km/h to 60 km/h, or a bike that

Physics
1 answer:
Stells [14]3 years ago
7 0

Answer:

they are the same

Explanation:

change in speed is 10km/h for both, and the time is the same for both. they have the same acceleration.

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Un paracaidista desciende desde 6 000 m de altura. Si la masa, con su equipo, es de 65 kg, ¿cuánto valdrá su energía potencial e
iris [78.8K]

Explanation:

PRIMERO ENCUENTRAS EL PESO DEL PARACAIDISTA

F_{peso} = 65 kg(9.80 m/s^{2}) = 637 N

CON LA FÓRMULA DE LA ENERGÍA POTENCIAL

U = 637 N(6000 m - 3500 m) = 1592500 J

3 0
3 years ago
The diagram shows four paths from point A to point B.
iVinArrow [24]
Path 2.

Displacement is the direction and magnitude of an object from its starting point, so path 2 is the direct route you would need to take to find direction and magnitude.
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2 years ago
Two tractors pull against a 1000 kg log. If the angle of the tractors' chains in relation to each other is 18.0° (each 9.0° from
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7 0
3 years ago
The magnitude of the weight of a 3.0 kg object on the surface of the earth is 29 N. True False
madreJ [45]
True

In fact, the weight of an object on the surface of the Earth is given by:
F=mg
where m is the mass of the object and g=9.81 m/s^2 is the gravitational acceleration on Earth's surface. If we use the mass of the object, m=3.0 kg, we find
F=mg=(3.0 kg)(9.81 m/s^2)=29 N
8 0
2 years ago
Two satellites are in circular orbits around the earth. The orbit for satellite A is at a height of 403 km above the earth’s sur
BARSIC [14]

Answer:

v_A=7667m/s\\\\v_B=7487m/s

Explanation:

The gravitational force exerted on the satellites is given by the Newton's Law of Universal Gravitation:

F_g=\frac{GMm}{R^{2} }

Where M is the mass of the earth, m is the mass of a satellite, R the radius of its orbit and G is the gravitational constant.

Also, we know that the centripetal force of an object describing a circular motion is given by:

F_c=m\frac{v^{2}}{R}

Where m is the mass of the object, v is its speed and R is its distance to the center of the circle.

Then, since the gravitational force is the centripetal force in this case, we can equalize the two expressions and solve for v:

\frac{GMm}{R^2}=m\frac{v^2}{R}\\ \\\implies v=\sqrt{\frac{GM}{R}}

Finally, we plug in the values for G (6.67*10^-11Nm^2/kg^2), M (5.97*10^24kg) and R for each satellite. Take in account that R is the radius of the orbit, not the distance to the planet's surface. So R_A=6774km=6.774*10^6m and R_B=7103km=7.103*10^6m (Since R_{earth}=6371km). Then, we get:

v_A=\sqrt{\frac{(6.67*10^{-11}Nm^2/kg^2)(5.97*10^{24}kg)}{6.774*10^6m} }=7667m/s\\\\v_B=\sqrt{\frac{(6.67*10^{-11}Nm^2/kg^2)(5.97*10^{24}kg)}{7.103*10^6m} }=7487m/s

In words, the orbital speed for satellite A is 7667m/s (a) and for satellite B is 7487m/s (b).

7 0
2 years ago
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