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ch4aika [34]
1 year ago
11

A fast teaub abd a ski train driving from city a and city b face to face the fast train has a speed of 76km/h, the slow train ha

s a speed of 65km/h. The fast train ent 40km more than the slow train when they met. The distance between the two cities is ___km
Physics
1 answer:
LekaFEV [45]1 year ago
7 0

The distance between the two cities is 513.24 km.

<h3>Time of motion when the two trains meet</h3>

The time spent on the journey when the two trains meet is calculated as follows;

(Va - Vb)t = d

where;

  • d is the distance between the trains before meeting

(76 - 65)t = 40

11t = 40

t = 40/11

t = 3.64 hr

<h3>Distance traveled by the fast train</h3>

d1 = 76 km/h x 3.64 h

d1 = 276.64 km

<h3>Distance traveled by the slow train</h3>

d2 = 65 km/h x 3.64 h

d2 = 236.6 km

The distance between the two cities = 276.64 km + 236.6 km

                                                             = 513.24 km

Learn more about relative velocity here: brainly.com/question/17228388

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Using the graph predict how many paper clipsa 7.5 v battery would pick up for both the 25 coil electromagnet and the 50 coil ele
enyata [817]

The graph between the strength of the magnet(number of paper clips picked) and battery is approximately a straight line.

For 25 coil, with increase of 1.5 V battery voltage, the electromagnet picks about 5 more clips. So, for a 7.5 V battery, it would pick about 30 paper clips.

For 50 coil, with increase of 1.5 V battery voltage, the electromagnet picks about 15 more clips. So, for a 7.5 V battery, it would pick about 30 paper clips.

3 0
3 years ago
A thermometer is removed from a room where the temperature is 70° F and is taken outside, where the air temperature is 10° F. Af
vekshin1

Answer:

T=51.64^\circ F

t=180.10s

Explanation:

The Newton's law in this case is:

T(t)=T_m+Ce^{kt}

Here, T_m is the air temperture, C and k are constants.

We have

70^\circ F in t=0

So:

T(0)=70^\circ F\\T(0)=10^\circ F+Ce^{k(0)}\\70^\circ F=10^\circ F+C\\C=70^\circ F-10^\circ F=60^\circ F

And we have 60^\circ F in t=30 s, So:

T(30)=60^\circ F\\T(30)=10^\circ F+(60^\circ F)e^{k(30)}\\60^\circ F=10^\circ F+(60^\circ F)e^{k(30)}\\50^\circ F=(60^\circ F)e^{k(30)}\\e^{k(30)}=\frac{50^\circ F}{60^\circ F}\\(30)k=ln(\frac{50}{60})\\k=\frac{ln(\frac{50}{60})}{30}=-0.0061

Now, we have:

T=10^\circ F+(60^\circ F)e^{-0.0061t}(1)

Applying (1) for t=1 min=60s:

T=10^\circ F+(60^\circ F)e^{-0.0061*60}\\T=10^\circ F+(60^\circ F)0.694\\T=10^\circ F+41.64^\circ F\\T=51.64^\circ F

Applying (1) for T=30^\circ F:

30^\circ F=10^\circ F+(60^\circ F)e^{-0.0061t}\\30^\circ F-10^\circ F=(60^\circ F)e^{-0.0061t}\\-0.0061t=ln(\frac{20}{60})\\t=\frac{ln(\frac{20}{60})}{-0.0061}=180.10s

8 0
3 years ago
How does light from a headlamp use a lens and a mirror to produce a narrow beam?
Kryger [21]
The headlamp's concave mirror is open on one end, and the light bulb's filament is placed at or near the focus. (Sorry if this is Wrong)
4 0
2 years ago
Read 2 more answers
A 600 N force acts on an object with a mass of 50 kg. What is the resulting acceleration of the object?
DochEvi [55]

Answer:

<h3>The answer is 12 m/s²</h3>

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

a =  \frac{f}{m}  \\

f is the force

m is the mass

From the question we have

a =  \frac{600}{50}  =  \frac{60}{5}  \\

We have the final answer as

<h3>12 m/s²</h3>

Hope this helps you

4 0
2 years ago
Storage of unlimited quantities of energy in batteries is possible. TrueFalse
dangina [55]

False

It is impossible to get infinite energy let alone to put it inside one battery

3 0
3 years ago
Read 2 more answers
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