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1 year ago

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A fast teaub abd a ski train driving from city a and city b face to face the fast train has a speed of 76km/h, the slow train ha

s a speed of 65km/h. The fast train ent 40km more than the slow train when they met. The distance between the two cities is ___km

1 answer:

LekaFEV [45]1 year ago

7 0

The distance between the two cities is 513.24 km.

<h3>Time of motion when the two trains meet</h3>

The time spent on the journey when the two trains meet is calculated as follows;

(Va - Vb)t = d

where;

d is the distance between the trains before meeting

(76 - 65)t = 40

11t = 40

t = 40/11

t = 3.64 hr

<h3>Distance traveled by the fast train</h3>

d1 = 76 km/h x 3.64 h

d1 = 276.64 km

<h3>Distance traveled by the slow train</h3>

d2 = 65 km/h x 3.64 h

d2 = 236.6 km

The distance between the two cities = 276.64 km + 236.6 km

= 513.24 km

Learn more about relative velocity here: brainly.com/question/17228388

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Part of the question is missing. Complete question is:

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