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Margaret [11]
4 years ago
13

If the magnitude of the electric field at a distance of 7.8 cm from the center is 30500 n/c , what is the magnitude of the elect

ric field at 22.3 cm from the center? answer in units of n/c.
Physics
1 answer:
Romashka-Z-Leto [24]4 years ago
4 0
<span>3730 N/C The intensity of the electric field follows the inverse square law. Since everything except the distance is remaining constant, then the force will vary with the inverse square of the ratio of the change. So first, lets calculate the ratio of the change in distance. 22.3 / 7.8 = 2.858974359 And since we actually want the square of the distance... 2.858974359^2 = 8.173734385 And since the distance increased, that means the force will decrease. So we get 30500 / 8.173734385 = 3731.464538 Rounding to 3 significant figures gives 3730 N/C.</span>
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Why does a rocket have such great momentum even if it is moving at a slow speed?
Artist 52 [7]

Answer:

Rockets provide a wonderful example of Momentum Conservation. As momentum in one direction is given to the rocket's exhaust gases, momentum in the other direction is given to the rocket itself.

Explanation:

First, think of two masses connected by a lightweight (massless!) compressed spring. When the two spring apart, conservation of momentum tells us the Center of Mass remains where it was (or moving as it was).

PTot,i = p1i + p2i = 0 + 0 = 0

PTot,f = p1f + p2f = PTot,i = 0

p1f + p2f = - m1 v1f + m2 v2f = 0

4 0
3 years ago
Read 2 more answers
A 10 kg box hangs from a rope. What is the tension in the rope (in Newtons) if the box is stationary
Archy [21]

Answer:

T = 98 N

Explanation:

The gravity of the earth is known to be 9.8 m/s²

Data:

  • m = 10 kg
  • g = 9.8 m/s²
  • T = ?

Use formula:

  • \boxed{\bold{T=m*g}}

Replace and solve:

  • \boxed{\bold{T=10\ kg*9.8\frac{m}{s^{2}}}}
  • \boxed{\boxed{\bold{T=98\ N}}}

The tension in the rope is <u>98 Newtons.</u>

Greetings.

5 0
3 years ago
Natural gas is very abundant in the United States. Compared to other fossil fuels, which describes the waste products of the com
SVETLANKA909090 [29]
Option d
. as they produce some hydrocarbon and methane etc
6 0
3 years ago
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(i) (a) what is the force per meter of length on a straight wire carrying a 9.75 a current when perpendicular to a 0.81 t unifor
Andrew [12]
The force generated by a magnetic field B perpendicular to a wire carrying a current I is
F=ILB
where L is the length of the wire.

If we divide both sides for L, we get
\frac{F}{L}=IB
where the ratio on the left is the force per meter of length, which is exactly what we want to find. So:
\frac{F}{L}=IB=(9.75 A)(0.81 A)=7.90 N/m
5 0
3 years ago
1. A jet lands on an aircraft carrier at a speed of 140 mi/h [ 1.00 mile = 1.61 km]
Iteru [2.4K]
Answer:

Acceleration, a = -31.29 m/s²

Explanation:

It is given that, Initial speed of the aircraft, u = 140 mi/h =

62.58 m/s

Finally, it stops, v = 0

Time taken, t = 2 s

Let a is the acceleration of the aircraft. We know that the rate of change of velocity is called acceleration of the object. It is given by :

a = t

0-62.58 2 a =

a = -31.29 m/s²

So, the acceleration of the aircraft is 31.29 m/s²

and the car is decelerating. Hence, this is the required solution.
(i found this answer becuase i could do the math)

5 0
3 years ago
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