The power that the light is able to utilize out of the supply is only 0.089 of the given.
Power utilized = (0.089)(22 W)
= 1.958 W
= 1.958 J/s
The energy required in this item is the product of the power utilized and the time. That is,
Energy = (1.958 J/s)(1 s) = 1.958 J
Thus, the light energy that the bulb is able to produce is approximately 1.958 J.
Answer:
When an electric field exists in a conductor a current will flow.
This implies a voltage difference between two points on the conductor.
Electrostatics pertains to static charge distributions.
That means that an object such as a charged spherical conductor will be at the same potential (voltage) on both its outer and inner surfaces.
Data Analysis and Conclusion
Answer:
28 m/s^2
Explanation:
distance, s = 14 m
time, t = 2 - 1 = 1 s
initial velocity, u = 0 m/s
Let a be the acceleration.
Use third equation of motion


a = 28 m/s^2
Thus, the acceleration is 28 m/s^2.
9.3 x 10⁻⁶N
Explanation:
Given parameters:
Mass 1 = 70kg
Mass 2 = 2000kg
distance = 1m
Unknown:
force between them =
Solution:
The force between the two masses will be a gravitational force of attraction.
F = 
G is universal gravitation constant = 6.67430×10−¹¹ N⋅m²/kg²
r is the distance between the two masses
Substituting the parameters:
F =
= 9.3 x 10⁻⁶N
Learn more:
Universal gravitation constant
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