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olasank [31]
3 years ago
10

A ladybug sits 14 cm from the center of a turntable spinning at 33.33 rpm. The Sun is shining horizontally through the window an

d the shadow of the ladybug can be seen traveling back and forth across the wall behind the turntable. What is the maximum velocity, in meters per second, of the shadow on the wall?
Physics
1 answer:
kolbaska11 [484]3 years ago
3 0

Answer:

The maximum velocity is 0.489 m/s

Explanation:

Maximum velocity (v) = angular velocity (w) × radius (r)

w = 33.33 rpm = 33.33×0.1047 = 3.4897 rad/s

r = 14 cm = 14/100 = 0.14 m

v = 3.4897×0.14 = 0.489 m/s

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The fast server in women's tennis is Venus Williams, who recorded a serve of 130   (209  ) in 2007.
Gemiola [76]
Converting 209 km/hr to m/s:
209 km/hr = 58.0 m/s
Contact distance = 0.1 m

Using the equation of motion:
2as = v² - u², where initial velocity is 0

a = (58)² / (2 x 0.1)
a = 1.68 x 10⁴ m/s²
7 0
4 years ago
How is temperature related to the physical change of a substance?
WINSTONCH [101]
When you heat something of cool it down you don't change the substance you might change the why is looks, but it is still the same substance. For example you cool water to 0 degrees Celsius it turns into ice but it still is two parts hydrogen and one part oxygen H2O. Physical changes will change state and/or form but it will still be what it originally was on the molecular level. Hope that helped. 
8 0
3 years ago
Read 2 more answers
calcular la longitud de un péndulo que oscila a 10 Hz en santa fe de bogota, sabiendo que en esta ciudad la aceleracion de la gr
cricket20 [7]

Answer:

L=2.48*10^{-3} m

Explanation:

The period equation for a pendulum is given by:

T=2\pi \sqrt{\frac{L}{g}}

and we know that T = 1/f, where f is the frequency, so we will have:

\frac{1}{f}=2\pi \sqrt{\frac{L}{g}}

Now, we just need to solve this equation for L.

\frac{1}{2\pi f}=\sqrt{\frac{L}{g}}

L=\frac{g}{(2\pi f)^{2}}

  • g is the gravity in Bogota (g=9.78 m/s^{2})
  • f is 10 Hz
  • L is the lenght of the pendulum

L=\frac{9.78}{(2\pi*10)^{2}}

L=2.48*10^{-3} m

I hope it helps you!

5 0
3 years ago
If the net work done on an object is zero, what can you determine about the object's kinetic energy?
jok3333 [9.3K]
The right answer for the question that is being asked and shown above is that: "The object's kinetic energy remains the same." If the net work done on an object is zero, you  determine about the object's kinetic energy is that The object's kinetic energy remains the same.

6 0
3 years ago
An Air Force plane lands with a velocity of 125 m/s and accelerates at a maximum rate of -6.5 m/s^2.
Alisiya [41]

Answer:

a) 19.2 s

b) No

Explanation:

Given:

v₀ = 125 m/s

a = -6.5 m/s²

v = 0 m/s

a) Find: t

v = at + v₀

(0 m/s) = (-6.5 m/s²) t + (125 m/s)

t ≈ 19.2 s

b) Find: Δx

v² = v₀² + 2aΔx

(0 m/s)² = (125 m/s)² + 2 (-6.5 m/s²) Δx

Δx ≈ 1200 m

An aircraft carrier that's 850 meters long won't be long enough.

8 0
4 years ago
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