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harina [27]
3 years ago
12

A race car accelerates uniformly from 18.5 m/s to 46.1 m/s in 2.47 seconds.

Physics
1 answer:
pochemuha3 years ago
6 0

Answer:

79.8 is the answere

I hope this HELP :)

Explanation:

Here, initial velocity is u=18.5m/s and final velocity is v=46.1m/s

Time taken t=2.47s

If a be the acceleration of the car.

Using v=u+at,

46.1=18.5+a(2.47)

⟹ a=11.17m/s

2

If d be the distance traveled by car.

Using formula v

2

−u

2

=2ad,

(46.1)

2

−(18.5)

2

=2(11.17)d

⟹ d=79.8m

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Two point charges are separated by 6 cm. The attractive force between them is 20 N. Find the force between them when they are se
Scorpion4ik [409]

Answer:

5 N

Explanation:

F_1 = 20 N

r_1 = 6 cm

r_2 = 12 cm

k = Coulomb constat

q = Charge

\dfrac{F_1}{F_2}=\dfrac{\dfrac{kq_1q_2}{r_1^2}}{\dfrac{kq_2q_2}{r_2^2}}\\\Rightarrow \dfrac{F_1}{F_2}=\dfrac{r_2^2}{r_1^2}\\\Rightarrow \dfrac{F_1}{F_2}=\dfrac{12^2}{6^2}\\\Rightarrow \dfrac{F_1}{F_2}=4\\\Rightarrow F_2=\dfrac{F_1}{4}\\\Rightarrow F_2=\dfrac{20}{4}\\\Rightarrow F_2=5\ N

The force is 5 N

7 0
3 years ago
Clear cutting has a similar effect as controlled burning of a forest. <br><br> True<br><br> False
mariarad [96]
<span>Clear cutting has a similar effect as controlled burning of a forest is True.


True </span>
3 0
3 years ago
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Which would be a common-sense practice in a lab environment?
algol13
Using safe research practices would be a very good common-sense practice in a lab environment.
6 0
3 years ago
A force of 70 N is inclined at an angle
Bad White [126]

Answer:

The horizontal component of the 70 N force = 35·√3 N

The vertical component of the 70 N force = 35 N

Explanation:

The magnitude of the given force, F = 70 N

The angle of inclination of the given force to the horizontal, θ = 30°

By the resolution of forces, we can resolve the given force, F, into its horizontal component, Fₓ, and vertical components, F_y, as follows;

The horizontal component of the given force = Fₓ = F × cos(θ)

Substituting the values, we have;

The horizontal component of the 70 N force, Fₓ = 70 × cos(30°) = 35·√3 N

The vertical component of the given force = F_y = F × sin(θ)

Substituting the values, we have;

The vertical component of the 70 N force, F_y = 70 × sin(30°) = 35 N.

5 0
3 years ago
Two soccer players, Mia and Alice, are running as Alice passes the ball to Mia. Mia is running due north with a speed of 5.30 m/
never [62]

Answer:

A. 2.83 m/s

B. 39.55 degrees north of east

Explanation:

The velocity of the ball relative to the ground is the sum vectors of velocity of the ball relative to Mia and the velocity of Mia relative to the ground

If we take north east as positive direction then

Velocity vector of the ball relative to Mia is

=  =

Velocity of Mia relative to gorund is

<0, 5.3>

So velocity of the ball relative to the ground is

<1.8, -3.12> + <0, 5.3> = <1.8, 2.18>

Its magnitude is:

v = \sqrt{v_e^2 + v_n^2} = \sqrt{1.8^2 + 2.18^2} = \sqrt{3.24 + 4.7524} = \sqrt{7.9924} = 2.83  m/s

Its direction is

tan\alpha = \frac{v_e}{v_n} = \frac{1.8}{2.18} = 0.83

\alpha = tan^{-1}0.83 = 0.69 rad \approx 39.55 degrees  north of east

4 0
3 years ago
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