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Hoochie [10]
2 years ago
7

An object accelerates 1.5m/s2 when a force of 7.0 newtons is applied to it. What is the mass of the object?

Physics
1 answer:
Lorico [155]2 years ago
5 0

The mass of an object that accelerates 1.5m/s² when a force of 7.0 newtons is applied to it is 4.67kg.

<h3>How to calculate mass?</h3>

The mass of an object can be calculated by dividing the force applied to the object by its acceleration. That is;

Mass = Force ÷ acceleration

According to this question, an object accelerates 1.5m/s² when a force of 7.0 newtons is applied to it. The mass of the object can be calculated as follows:

Mass = 7N ÷ 1.5m/s²

Mass = 4.67kg

Therefore, the mass of an object that accelerates 1.5m/s² when a force of 7.0 newtons is applied to it is 4.67kg.

Learn more about mass at: brainly.com/question/19694949

#SPJ1

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A driver in a 2000 kg Porsche wishes to pass to pass a slow-moving school bus on a four-lane road. What is the average power in
creativ13 [48]

Answer:

The power require to accelerate the car is, P = 299700 watts

Explanation:

Give data,

The mass of the car, m = 2000 kg

The initial velocity of the sports car, u = 30 m/s

The final velocity of the sports car, v = 60 m/s

The time period of acceleration, t = 9 s

The acceleration of the car, a =  (v-u) / t

                                                  = (60 - 30) / 9

                                                  = 3.33 m/s²

The displacement of the car,

                                               S = ut + ½ at²

                                                  = 30 x 9 + ½ x 3.33 x 9²

                                                  = 405 m

The force acting on the car, F = m x a

                                                  = 2000 x 3.33

                                                  = 6660 N

The work done by the car, W = F  S

                                                  = 6660 x 405

                                                  = 2697300 J

The power of the car,           P = W / t

                                                  = 2697300 / 9

                                                  = 299700 watts

Hence, the power require to accelerate the car is, P = 299700 watts

4 0
4 years ago
.Imagine that you pushed a box, applying a force of 60 newtons, over a distance of 4 meters. how much work have you done? 15 jou
DaniilM [7]
Work=force X distance
Newtons is a measurement of force
4 meters is your distance 60×4=240

240 joules
5 0
3 years ago
Read 2 more answers
An electric heater is rated at 1400 W, a toaster is rated at 1150 W, and an electric grill is rated at 1560 W. The three applian
gayaneshka [121]

Answer:

The current in the heater is 12.5 A

Explanation:

It is given that,

Power of electric heater, P₁ = 1400 W

Power of toaster, P₂ = 1150 W

Power of electric grill, P₃ = 1560 W

All three appliances are connected in parallel across a 112 V emf source. We need to find the current in the heater. We know that in parallel combination of resistors the current flowing in every branch of resistor divides while the voltage is same.

Electric power, P_1=V\times I_1

I_1=\dfrac{P_1}{V}

I_1=\dfrac{1400\ W}{112\ V}

I_1=12.5\ A

So, the current in the heater is 12.5 A. Hence, this is the required solution.  

8 0
4 years ago
A car travels north for 20 km. The car then travels south for 35 km.
PSYCHO15rus [73]

Answer: -15 km

Explanation:

8 0
3 years ago
Most cars have a coolant reservoir to catch radiator fluid that may overflow when the engine is hot. A radiator is made of coppe
alexandr402 [8]

Answer:

0.699 L of the fluid will overflow

Explanation:

We know that the change in volume ΔV = V₀β(T₂ - T₁) where V₀ = volume of radiator = 21.1 L, β = coefficient of volume expansion of fluid = 400 × 10⁻⁶/°C

and T₁ = initial temperature of radiator = 12.2°C and T₂ = final temperature of radiator = 95.0°C

Substituting these values into the equation, we have

ΔV = V₀β(T₂ - T₁)

= 21.1 L × 400 × 10⁻⁶/°C × (95.0°C - 12.2°C)

= 21.1 L × 400 × 10⁻⁶/°C × 82.8°C = 698832 × 10⁻⁶ L

= 0.698832 L

≅ 0.699 L = 0.7 L to the nearest tenth litre

So, 0.699 L of the fluid will overflow

6 0
3 years ago
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