C whales have similar DNA to elephants
Answer:
a) A1 = 
b) A1 = 2.688 cm
c) Q1 = A1 x v1
d) v1 = 3.1994 m/s
e) A2 = 
f) A2 = 0.7963cm
Explanation:
a) Area = 
r = 
thus,
area = 
A1 = ![\frac{\pi (d1)^{2} }{4}[/tex]b) d1 = 1.85 cmsubstituting in the above equation,A1 = [tex]\frac{\pi (d1)^{2} }{4}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cpi%20%28d1%29%5E%7B2%7D%20%7D%7B4%7D%5B%2Ftex%3C%2Fstrong%3E%5D%3C%2Fp%3E%3Cp%3E%3C%2Fp%3E%3Cp%3Eb%29%20d1%20%3D%201.85%20cm%3C%2Fp%3E%3Cp%3Esubstituting%20in%20the%20above%20equation%2C%3C%2Fp%3E%3Cp%3EA1%20%3D%20%20%5Btex%5D%5Cfrac%7B%5Cpi%20%28d1%29%5E%7B2%7D%20%7D%7B4%7D)
A1 = 
A1 = 2.688 cm
c) Flow rate = Area x velocity ( refer brainly.com/question/13997998)
Q1 = A1 x v1
d) From the above equation,
v1 = 
= 
= 319.94 cm/s = 3.1994 m/s
e) Since the flow rate Q1 is constant throughout the hose, Av is a constant.
i.e. A1 x v1 = A2 x v2
thus,
A2 =
f) v2 = 10.8 m/s.
substituting the values in the above equation,
A2 = 
= 0.7963cm
Answer:
A thermistor is an electrical device, a thermally sensitive semiconductor resistor, whose resistance changes in response to temperature. Thermistors are made in a variety of ways including thin films (SiC).
Explanation:
hope it helps
Answer:
(a) F = 1500 N.
(b) Ratio force to the antelepe's weight = 3.40
Explanation:
Force : This can be defined as the product of mass and the distance moved by a body. Its S.I unit is Newton. It can be represented mathematically as
F = Ma
Where F= force, M = mass (Kg) and a = Acceleration (m/s²)
Weight: This can be defined as the force on a body due to gravitation field. It is also measured in Newton (N). It can be represented mathematically as
W = Mg
Where W = weight of the body, M = mass of the body (Kg), g = Acceleration due to gravity.
(a)
F = Ma
Where M = 45kg,
a = unknown.
But we can look for acceleration Using one of the equation of motion,
v² = u² + 2gs
Where v= final velocity(m/s), u = initial velocity (m/s) g = 0 m/s, g = 9.8m/s² and s = height = 2.5m.
∴ v² = 2gs
v = √2gs = √(2×9.8×2.5)
v= √49 = 7m/s
With the force applied, the impala’s velocity must increase from 0 m/s to 7 m/s in 0.21 second
∴ a = (v-u)/t
a = (7-0)/0.21 = 7/0.21
a = 33.33 m/s².
F = 45 × 33.33 ≈ 1500
F = 1500 N.
(b)
Where F = Force = 1500 N
and W = Weight = Mg = 45 × 9.8 = 441 N
∴Ratio force to the antelepe's weight = F/W = 1500/441 = 3.40
Ratio force to the antelepe's weight = 3.40
