Answer:
let length be l
breadth=l-10m
area of rectangular park=236m²
Step-by-step explanation:
area of rectangular park=236m²
l×(l-10)=236
l²-10l-236=0
l²-2.l.5+5²-236-5²=0
(l-5)²-236-25=0
(l-5)²=261
(l-5)=√261
(l-5)=16.15
l=16.15+5=21.15
b=l-10=21.15-10=11.15
Answer:
For the tickets sold collum, your going to do 1,2,3,4,5,6,7 and for the total revenue, your going to do 34.00 68.00 102.00 136.00 170.00 204.00 238.00
Step-by-step explanation:
Then for ordered pairs, you´re going to do 1, 34.00 2, 68.00 3, 102.00 and so on. Then you graph it, oh and K= 34.00
Three of those statements are true.
The only one that is NOT correct is:
<span>Any quadrilateral with one right angle is a rectangle.
</span>
I hope this helps you
(fog)(5)=f (g (5))=?
x= 5 g (5)=-4.5+3=-20+3=-17
f (g(5))=f (-17)=-2. (-17)-7
f (-17)=34-7
f (-17)=27
From the statement of the problem, we know that:
• a train starts at City A and travels 2,158 km to City B,
,
• then it travels 3,793 km from City B to City C.
The distance between City A and City C is equal to the sum of the distance from City A to City B, and the distance from City B to City C. So the distance between City A and City C is 2,158 km + 3,793 km = 5951 km.
Looking at the answer of Clay:
<em>2,158 + 3,793 = (2,158 + 7) + (3,793 + 7) = 2,165 + 3,800 = 5,965</em>
We see that he added 7 km to each of the distances, that's the reason why he found a different a wrong result.
