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1 year ago

Solve the equation for the given variable. justify each step.

Mathematics

1 answer:

s344n2d4d5 [400]1 year ago

5 0

Answer: y= $\frac{5-9x}{2}$

s=-30+10t

Step-by-step explanation:

9x + 2y = 5; y

9x-9x+2y = 5-9x

2y=5-9x

y= $\frac{5-9x}{2}$

1/15s - 2/3t = -2; s

(1/15s - 2/3t = -2)*15 ==> Get rid of fraction by multiplying both sides by 15

s - 30/3 t=-30

s-10t=-30

s=-30+10t

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A french class has a total of 25 student.The number of males is 7 more than the number of females how many males and how many fe

Lady_Fox [76]

Answer:

16 males and 9 females

Step-by-step explanation:

To solve this we can use a system of equations.

Let's start by naming the number of females x.

The number of males would then be y.

<u>Using these variables, we can set up 2 equations using info provided:</u>

A french class has a total of 25 students, -> x+y=25

The number of males is 7 more than the number of females -> x+7=y

Use substitution to solve.

<u>From the second equation:</u>

x+7=y

Subtract 7 from both sides.

x=y-7

Substitute that into the first equation.

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Combine like terms.

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3 0

2 years ago

Read 2 more answers

A manufacturer of tires wants to advertise a mileage interval that ex-cludes no more than 10% of the mileage on tires he sells.

Sergio039 [100]

Answer:

This mileage interval is from 30120 miles and higher.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

All he knows is that, for a large number of tires tested, the mean mileage was 25,000 miles, and the standard deviation was 4000 miles. This means that $\mu = 25000, \sigma = 4000$ .

A manufacturer of tires wants to advertise a mileage interval that ex-cludes no more than 10% of the mileage on tires he sells. What interval wouldyou suggest?

The lower end of this interval is X when Z has a pvalue of 0.90. That is $Z = 1.28$ .

$Z = \frac{X - \mu}{\sigma}$

$1.28 = \frac{X - 25000}{4000}$

$X - 25000 = 4000*1.28$

$X = 30120$

This mileage interval is from 30120 miles and higher.

7 0

2 years ago