The perimeter = 20 and AC = 8
Now as it is not mentioned which sides are equal of the isosceles triangle ABC,
We have two possible situations.
1)
If AC is the base
In that case AB = BC
Now AC = 8, AB = x , BC = x
So x + x + 8 = 20
2x + 8 = 20
2x = 12
x = 6
AB = BC = 6
2)
IF AC is not the base,
Then
AC = BC or AC = AB
So BC = 8 or AB = 8
If AB = AC = 8
Then
BC + 8 + 8 = 20
BC = 4
So there are two possible lengths of BC
Either it is BC = 8 or BC = 6 or BC = 4
The figure is attached for your reference.
I am not sure if the “+” was supposed to go there or if that was just a typo, so I do apologize if this is wrong... but if it doesn’t belong in the equation at all, 20 = 2X is a fairly simply multiplication problem. You are to divide both sides by the 2 and you should get X = 10, because 2 goes into 20, 10 times; and the 2 goes into 2 only once, therefore the 2 now gets cancelled out.
Answer: 20 divided by 2 = 2x divided by 2 is now 10 = X.
Really hope this helps you, have a good day :)
Answer:
10x - 3
Step-by-step explanation:
First, distribute 2 to all terms within the second parenthesis:
2(3x + 1) = (2 * 3x) + (2 * 1) = 6x + 2
4x - 5 + 6x + 2
Combine like terms (terms with the same amount of variables).
4x + 6x + 2 - 5
(4x + 6x) + (2 - 5)
10x + (-3)
10x - 3
10x - 3 is your answer.
~
Log3 (x) + 4125=3 final answer
I’ll check it give me a minute I’m mainly writing this so I know to come to this just sec
