Answer:
25
Step-by-step explanation:
5²=25
Locating astronomical objects with reference to equatorial coordinate system on the celestial sphere is called spherical astronomy. It is one of the oldest observational astronomical branch which uses various mathematical concepts specifically, geometry calculation for measurement estimation. It can also be referred as positional astronomy generally envelops entire earth geometry to analysis.
Basically, it includes different parameters of earth's geometry along with its equator in line to celestial objects which finally gives location of these objects in particular year. All in all, it is a specialized science field in astronomy which first observes around space envelope and finally gives data about location of individual space objects with respect to tome.
Answer:
0.21
Step-by-step explanation:
Answer:
a = -12
b = 3
Step-by-step explanation:
second term = a + 6b
to find the 5th term, notice the pattern (since this is a linear equation, each term increases by the same amount) and each term increases by 4b: 2b -> 6b -> 10b.
therefore, the 4th term would be a+14b and the 5th would be a+18b
so a + 6b = 8
and a + 18b = 44
u now have two simultaneous equations, which can be solved through substitution or elimination. I'm gonna use elimination because it's quicker in this case:
steps: (since the a would cancel out by subtracting, subtract then solve for b. divide by -12 on both sides to isolate the b)
now that u know the value of b, substitute it into an equation to solve for a:
a + 6b = 8
a + 6(3) = 8
a + 24 = 8
a = 8 - 24
a = -16
hope this helps!
Step-by-step explanation:
<em>1st year</em>:
(1200 x 3.5 x 1) ÷ 100 = $42
<em>2nd year:</em>
(1242 x 3.5 x 1) ÷ 100= $43.47
<em>3rd year:</em>
(1285.47 x 3.5 x 1) ÷ 100= $44.99≈ $45
<em>4th year:</em>
(1330.47 x 3.5 x 1) ÷ 100= $46.56
Compound interest:
$(42 + 43.47 + 45 + 46.56)
=<u>$ 177.03</u>
