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2 years ago

Find the volume of a box with length 25 cm, height 25 cm and width 1.0 m. Volume

Chemistry

1 answer:

mariarad [96]2 years ago

4 0

The volume of a box with length 25 cm, height 25 cm and width 1.0 m is 0.0625m³.

Volume of the box which is a cuboid can be calculated by multiplying the length, breadth and height of the given box.

Volume of the box is given by the product of the length of the box, Height of the box and Breadth or width of the box.

Since, the box is a cuboid, hence the formula is given by the products of length, breadth and height.

Given,

length of the box= 25cm = 0.25m

Height of the box =25cm = 0.25m

width of the box= 1m

Volume = length × width × height of box

Volume = 0.25 × 0.25 × 1

Volume = 0.0625m³

The volume of the box is 0.0625m³.

Learn more about Volume here, brainly.com/question/23118276

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polet [3.4K]

Answer:

Explanation:

Step 1: Calculate the amount of sodium hydroxide in moles

Volume of sodium hydroxide solution = 25.0 ÷ 1,000 = 0.0250 dm3

Rearrange:

Concentration in mol/dm3 =

Amount of solutein mol = concentration in mol/dm3 × volume in dm3

Amount of sodium hydroxide = 0.100 × 0.0250

= 0.00250 mol

Step 2: Find the amount of hydrochloric acid in moles

The balanced equation is: NaOH(aq) + HCl(aq) → NaCl(aq) + H2O(l)

So the mole ratio NaOH:HCl is 1:1

Therefore 0.00250 mol of NaOH reacts with 0.00250 mol of HCl

Step 3: Calculate the concentration of hydrochloric acid in mol/dm3

Volume of hydrochloric acid = 20.00 ÷ 1000 = 0.0200 dm3

Concentration in mol/dm3 =

= 0.125 mol/dm3

Step 4: Calculate the concentration of hydrochloric acid in g/dm3

Relative formula mass of HCl = 1 + 35.5 = 36.5

Mass = relative formula mass × amount

Mass of HCl = 36.5 × 0.125

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So concentration = 4.56 g/dm3

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3 years ago

________ is a measure of the amount of matter in an object.

Zepler [3.9K]

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3 years ago

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3 years ago

0.200 grams of HCl is dissolved in 0.801 grams water. The density of the solution formed is 1.10 g/mL. What is the molarity of t

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Answer:

$M=6.03M$

Explanation:

Hello,

In this case, since the molarity is computed by:

$M=\frac{n_{solute}}{V_{solution}}$

Whereas the solute is the hydrochloric acid, we compute the corresponding moles with its molar mass (36.45 g/mol):

$n_{solute}=0.200gHCl*\frac{1molHCl}{36.45gHCl} =0.00549molHCl$

Next, since the solution contains both HCl and water, we compute the volume in liters by using its density:

$V_{solution}=(0.200+0.801)g*\frac{1mL}{1.10g} *\frac{1L}{1000mL} =9.1x10^{-4}L$

Therefore, the molarity turns out:

$M=\frac{0.00549mol}{9.1x10^{-4}L}\\ \\M=6.03M$

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3 years ago

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