Question

0.200 grams of HCl is dissolved in 0.801 grams water. The density of the solution formed is 1.10 g/mL. What is the molarity of the solution

Answer 1

Answer:

$M=6.03M$

Explanation:

Hello,

In this case, since the molarity is computed by:

$M=\frac{n_{solute}}{V_{solution}}$

Whereas the solute is the hydrochloric acid, we compute the corresponding moles with its molar mass (36.45 g/mol):

$n_{solute}=0.200gHCl*\frac{1molHCl}{36.45gHCl} =0.00549molHCl$

Next, since the solution contains both HCl and water, we compute the volume in liters by using its density:

$V_{solution}=(0.200+0.801)g*\frac{1mL}{1.10g} *\frac{1L}{1000mL} =9.1x10^{-4}L$

Therefore, the molarity turns out:

$M=\frac{0.00549mol}{9.1x10^{-4}L}\\ \\M=6.03M$

Regards.