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lesya692 [45]
3 years ago
10

Using Models to Answer Questions About Systems

Chemistry
2 answers:
oksian1 [2.3K]3 years ago
8 0
^^ what he or she said
viva [34]3 years ago
5 0
1A: The legs can be a adjusted, as well as the sand can be swapped out. It’s a very good design for running multiple tests.
1B: He could add books or something under the front or back legs in order to increase/decrease the incline, therefore imitating the hypothesis.
1C: He can change out the sand grains to finer ones, or coarser ones, and record his results of each test.
2: If he sets the model at a steep incline and tests it with coarse sand and fine sand, seeing which one makes a narrower, deeper hole.
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1. What % of the nation's energy is used by the Industrial<br> Sector?
kari74 [83]

Answer:

Petroleum:92 Percent

Natural Gas:3 Percent

Renewable energy:5 Percent

Explanation:

US primary energy consumption by source and sector (2017)[17]

Supply sources Percent of source Demand sectors Percent of sector

Petroleum

36.2% 72% Transportation

23% Industrial

5% Residential and commercial

1% Electric power Transportation

28.1% 92% Petroleum

3% Natural gas

5% Renewable energy

Natural gas

28.0% 3% Transportation

35% Industrial

28% Residential and commercial

34% Electric power Industrial

21.9% 38% Petroleum

45% Natural gas

5% Coal

12% Renewable energy

Coal

13.9% 9% Industrial

<1% Residential and commercial

91% Electric power Residential and commercial

10.4% 16% Petroleum

76% Natural gas

<1% Coal

8% Renewable energy

Renewable energy

11.0% 13% Transportation

23% Industrial

7% Residential and commercial

57% Electric power Electric power

37.2% 1% Petroleum

26% Natural gas

34% Coal

17% Renewable energy

23% Nuclear electric power

Nuclear electric power

8.4% 100% Electric power  

3 0
3 years ago
Nitric acid is produced commercially by the Ostwald process, represented by the following equations. 4 NH3(g) + 5 O2(g) 4 NO(g)
Marrrta [24]

Answer:

The answer to your question is: 1538095.2 kg of NH3

Explanation:

MW HNO3 = 63 kg

MW NO2 = 46 kg

                         3 NO2(g) + H2O(l)--- 2 HNO3(aq) + NO(g)

                            3(46) kg--------------   2(63) kg  

                                  x     ---------------  7600000 kg

           x = 7600000 x 138/126 = 8323809.5 kg og NO2

MW NO = 30            

                         2 NO(g) + O2(g)---2 NO2(g)

                       2(30) ------------------2(46)

                        x        ---------------- 8323809.5 kg  

             x = 8323809.5 x 60/92 = 5428571.4 kg of NO

MW NH3 = 17 kg

                      4 NH3(g) + 5 O2(g) 4 NO(g) + 6 H2O(g)

                       4(17) -------------------- 4(30)

                         x ----------------------- 5428571.4

x = 5428571.4 x 34 / 120

x = 1538095.2 kg of NH3

4 0
2 years ago
NO LINKS PLEASE! Why does dye dropped into a cup of water eventually spread throughout the water?
Nezavi [6.7K]

Answer:

C

Explanation:

okay, you need to look at the structures of the particles of matter in the solid, liquid and gas.

  • particles in a solid are in fixed positions, where they can only vibrate in those positions ( take a look at ice, or rather, a brick)
  • liquids have very small or rather, no spaces between them, but they can slide or rub against each other, like people in a <em>really tight</em> crowd I guess
  • gas particles have very large spaces between them and they move randomly. these exibit what's called brownian motion.
  • since water particles (and all other liquid particles) have negligible spacings and limited movement, that allows the dye particles to move from a region of high concentration to that of a low concentration. the aim for this is for the mixture/solution to reach an equilibrium, that  is the mixture must get to a point where all regions have the same concentration of the dye.

you can refer to your coursebooks :)

correct where wrong please:)

5 0
2 years ago
Do step 3 as outlined in the lab guide. Record your results in the appropriate blanks.
PolarNik [594]

Explanation:

Do the step 3 as outlined in the lab guide. record your results in the appropriate blank.

D

8 0
3 years ago
The mass of a solid substance is 21.112 g. If the volume of the solid substance is 19.5 cm3, calculate the density of the substa
Ostrovityanka [42]

Answer:

ρ = 1.08 g/cm³

Explanation:

Step 1: Given data

Mass of the substance (m): 21.112 g

Volume of the substance (V): 19.5 cm³

Step 2: Calculate the density of the substance

The density (ρ) of a substance is equal to its mass divided by its volume.

ρ = m / V

ρ = 21.112 g / 19.5 cm³

ρ = 1.08 g/cm³

The density of the substance is 1.08 g/cm³.

6 0
3 years ago
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