Vanillin, C8H8O3, is the active ingredient in vanilla flavoring. It contains a six-membered aromatic ring with an aldehyde group
on carbon 1, an alkoxy group (ether) on carbon 3, and a hydroxyl group (alcohol) on carbon 4. Draw the structure of vanillin.
1 answer:
Answer:
The answer is in the picture attached
Explanation:
A six-membered aromatic ring is one of the most common structures in natural compounds.
The aldehyde group in position one consist in one carbon double-bonded to oxygen and bonded to hydrogen.
The alkoxy group in position three consist in a oxygen bonded to an alkyl group (The simplest alkyl group is methyl -CH₃-).
There is, in position four, an hydroxyl group -OH. bonded to this six-membered aromatic ring.
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Answer:
1.
2.
3.The electron affinity of is zero.
4.
Explanation:
1.
<u>Electron affinity:</u>
It is defined as the amount of energy change when an electron is added to atom in the gaseous phase.
The electron affinity of is as follows.
2.
<u>Ionization energy</u>:
Amount of energy required to removal of an electron from an isolated gaseous atom.
The third ionization energy of Titanium is as follows.
3.
The electronic configuration of Mg:
By the removal of two electrons from a magnesium element we get ion.
has inert gas configuration i.e,
Hence, it does not require more electrons to get stability.
Therefore,the electron affinity of is zero.
4.
The ionization energy of is follows.
Answer:
Three hydrogen atoms to form PH₃.
Explanation:
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In this case, since the elements belonging to the nitrogen family (N, P, As, Sb and Bi) show five valence electrons, because there are five electrons at their outer shell, it is clear that if phosphorous bonds with hydrogen, it is going to require the same amount of oxygen atoms (3) because elements having five valence electrons need 3 bonds in order to attain the octet (5+3=8).
Therefore the compound would be:
Which is phosphine.
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