Vanillin, C8H8O3, is the active ingredient in vanilla flavoring. It contains a six-membered aromatic ring with an aldehyde group
on carbon 1, an alkoxy group (ether) on carbon 3, and a hydroxyl group (alcohol) on carbon 4. Draw the structure of vanillin.
1 answer:
Answer:
The answer is in the picture attached
Explanation:
A six-membered aromatic ring is one of the most common structures in natural compounds.
The aldehyde group in position one consist in one carbon double-bonded to oxygen and bonded to hydrogen.
The alkoxy group in position three consist in a oxygen bonded to an alkyl group (The simplest alkyl group is methyl -CH₃-).
There is, in position four, an hydroxyl group -OH. bonded to this six-membered aromatic ring.
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Answer:
%C = 56,1%
%H = 5,5%
%Cl = 27,6%
%N = 10,8%
Explanation:
The moles of CO₂ are the same than moles of C in the herbicide.
Moles of H₂O are ¹/₂ of moles of H in the herbicide.
Moles of CO₂ are obtained using:
n = PV/RT
Where, in STP: P is 1 atm; V is 0,2092L; R is 0,082atmL/molK; T is 273 K
moles of CO₂ are: 9,345x10⁻³ mol≡ mol of C×12,01g/mol = <em>0,1122 g of C ≡ 112,2mg of C</em>
In the same way, moles of H₂O are 5,450x10⁻³mol×2 =0,1090 mol of H×1,01g/mol = <em>0,0110 g of H ≡ 11,0mg of H</em>
As you have 55,14 mg of Cl, the mg of N are:
200,0mg - 112,2 mg of C - 11,0 mg of H - 55,14 mg of Cl = 21,66 mg of N
Thus, precent composition of the herbicide is:
%C = ×100 = 56,1%C
%H = ×100 = 5,5%H
%Cl = ×100 = 27,6%Cl
%N = ×100 = 10,8%N
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