The net displacement of the object from t = 0s to t = 8s is 2 m.
The initial velocity of the object is 1 m/s.
The final velocity of the object is 0 m/s.
The average velocity of the object from t = 0s to t = 8s is 0.25 m/s.
The distance traveled by the object in the first 8 seconds is 6 m.
<h3>
What is the displacement of the object?</h3>
The displacement of the object is the change in the position of the object.
d = Δx
d = x(0) = x(8)
d = 2 m - 0 m = 2m
<h3>Initial velocity of the object</h3>
v = x/t
v = 2m / 2 s
v = 1 m/s
<h3>Final velocity of the object</h3>
v = x/t
v = 0/8 s = 0 m/s
<h3>Average velocity of the object</h3>
v(avg) = Δx/Δt = 2 m/8 s = 0.25 m/s
<h3>Distance traveled by the object in the first 8 seconds</h3>
in the first 2 seconds = 2 m
in the first 6 seconds = 4 m
in the first 8 seconds = 2 m + 4 m + 0 = 6 m
Thus, the net displacement of the object from t = 0s to t = 8s is 2 m.
The initial velocity of the object is 1 m/s.
The final velocity of the object is 0 m/s.
The average velocity of the object from t = 0s to t = 8s is 0.25 m/s.
The distance traveled by the object in the first 8 seconds is 6 m.
Learn more about final velocity here: brainly.com/question/25905661
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