Ask question

Ask question

All categories

Liono4ka [1.6K]

3 years ago

11

How are tensional forces created?

1 answer:

dezoksy [38]3 years ago

6 0

Tensional forces are created on a piece of string or rope or anything similar when it is pulled tight from both sides, that is, when forces are acting on both ends, thus tightening it. <span>The tension force is directed along the length of the wire and pulls equally on the objects on the opposite ends of the wire.</span>

You might be interested in

Why a magnet sitting next to a wire does not induce a current in the wire

SSSSS [86.1K]

A magnet sitting next to a wire does not induce a current in the wire because <span> the magnet is very small and short compared to the coil radius. If you pretend it's two individual monopoles, they're only a few mm apart, so at several cm there's almost perfect cancellation of the fields.</span>

5 0

3 years ago

A line with a negative slope on a distance-time graph means the object is?

otez555 [7]

Answer:negative slope or gradient I think

Explanation:

4 0

3 years ago

Read 2 more answers

According to the general theory of relativity, what are consequences of the curvature of space-time? Check all that apply. The d

Svetlanka [38]

Answer:

The dilation of time.

The falling of objects.

The changing of paths of light.

Explanation:

I have explained in the image attached below.

From the explanation, the correct ones are;

The dilation of time.

The falling of objects.

The changing of paths of light.

4 0

3 years ago

Oque ocorre com a velocidade se diminuímos o tempo, mantendo a distância constante? E se aumentarmos o tempo? Que tipo de grande

spin [16.1K]

No se
Pero if I did I would help you

4 0

3 years ago

A standard baseball has a circumference of approximately 23 cm . if a baseball had the same mass per unit volume as a neutron or

Svetlanka [38]

<u>Answer:</u>

Mass of base ball $m_b=3.992*10^{14}kg$

<u>Explanation:</u>

Circumference of baseball = 2πr = 23 cm

So radius of baseball = 3.66 cm = $3.66*10^{-2}$ m

Mass per unit volume of baseball = Mass per unit volume of neutron or proton.

Mass of proton = $10^{-27}$ kg

Diameter of proton = $10^{-15}$ m

Radius of proton = $5*10^{-16}$ m

Volume of ball = $\frac{4}{3} \pi r^3$

Now substituting all values in Mass per unit volume of baseball = Mass per unit volume of neutron or proton.

$\frac{m_b}{\frac{4}{3}\pi *(3.66*10^{-2})^3} =\frac{10^{-27}}{\frac{4}{3}\pi *(5*10^{-16})^3}$

$\frac{m_b}{(3.66*10^{-2})^3} =\frac{10^{-27}}{(5*10^{-16})^3}$

$m_b=3.992*10^{14}kg$

So mass of base ball $m_b=3.992*10^{14}kg$

5 0

4 years ago

Read 2 more answers