A rope of negligible mass is wrapped around a 225-kg solid cylinder of radius 0.400 m. the cylinder is suspended several meters
off the ground with its axis oriented horizontally, and turns on that axis without friction. (a) if a 75.0-kg man takes hold of the free end of the rope and falls under the force of gravity, what is his acceleration? (b) what is the angular acceleration of the cylinder? (c) if the mass of the rope were not neglected, what would happen to the angular accelera- tion of the cylinder as the man falls?
1 answer:
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Answer:
4847.94844926 kg/m³
Explanation:
= Actual density of cube = 1900 kg/m³
= Density change due to motion
v = Velocity of cube = 0.92c
c = Speed of light =
Relativistic density is given by
The cube's density as measured by an experimenter in the laboratory is 4847.94844926 kg/m³
Answer:
<h2>6 m/s²</h2>Explanation:
The acceleration of an object given it's mass and the force acting on it can be found by using the formula
f is the force
m is the mass
From the question we have
We have the final answer as
<h3>6 m/s²</h3>Hope this helps you