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sashaice [31]
3 years ago
12

Red light from three separate sources passes through a diffraction grating with 5.60×105 slits/m. The wavelengths of the three l

ines are 6.56 ×10−7m (hydrogen), 6.50 ×10−7m (neon), and 6.97 ×10−7m (argon).
Part A
Calculate the angle for the first-order diffraction line of first source (hydrogen).
Express your answer using three significant figures.
θH = ∘
Part B
Calculate the angle for the first-order diffraction line of second source (neon).
Express your answer using three significant figures.
θNe = ∘
Part C
Calculate the angle for the first-order diffraction line of third source (argon).
Express your answer using three significant figures.
θAr = ∘
Physics
1 answer:
shtirl [24]3 years ago
6 0

Answer:

I can help

Explanation:

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Part 1- The work done by the gas during this process will be 5.65 ×10⁻³ kJ.

Part 2-The heat added to the gas during this process will be 5.65 ×10×10⁻³ kJ.

<h3>What is work done by the gas?</h3>

Work is the product of pressure p and volumes V during a volume change for such a gas. The work seems to be the area under the curve that indicates how the state changes.

The work done under the isothermal process is;

\rm W= P_1V_1 log_e(\frac{P_1}{P_2} )\\\\ W= 7 \times 1.71429  \times 10^{-3} log_e(\frac{7 }{2} )\\\\\ W= 0.0044 \  kJ

For the isothermal process;

ΔU=0

\rm \triangle Q = \triangle E + \triangle W \\\\ Q =  0 + 5.65 \times 10^{-3}\\\\ Q = 5.65 \TIMES 10^{-3} \ kJ

Hence, the work done, and the heat added by the gas during this process will be 5.65 ×10⁻³ kJ and 5.65 ×10×10⁻³ kJ respectively.

To learn more about work done by the gas, refer to the link;

brainly.com/question/12539457

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