The energy carried by a single photon of frequency f is given by:
where
is the Planck constant. In our problem, the frequency of the photon is
, and by using these numbers we can find the energy of the photon:
Answer:
D
Explanation:
First we define our variables
V0=29.4
a=-9.8
V=0
We have to find the maximum displacement , which I will define as X
We use formula v^2=v0^2+2aX
All we do is substitute our values
0=29.4^2-19.6X
29.4^2=19.6X
X=29.4^2/19.6=44.1
Answer:
The new current in the straight wire is 4.98 A
Explanation:
Given;
initial magnetic force on the wire, F₁ = 0.017 N
initial current flowing on the straight wire, I₁ = 1.1 A
When the current in the wire is changed,
new magnetic force on the wire, F₂ = 0.077 N
the new current in the wire, I₂ = ?
Applying equation of magnetic force on conductor;
F₁ = I₁BLsinθ
F₂ = I₂BLsinθ
BLsinθ = F₁/I₁ = F₂/I₂
I₂ = (F₂I₁)/F₁
I₂ = (0.077 x 1.1) / 0.017
I₂ = 4.98 A
Therefore, the new current in the straight wire is 4.98 A
