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sashaice [31]
3 years ago
12

Red light from three separate sources passes through a diffraction grating with 5.60×105 slits/m. The wavelengths of the three l

ines are 6.56 ×10−7m (hydrogen), 6.50 ×10−7m (neon), and 6.97 ×10−7m (argon).
Part A
Calculate the angle for the first-order diffraction line of first source (hydrogen).
Express your answer using three significant figures.
θH = ∘
Part B
Calculate the angle for the first-order diffraction line of second source (neon).
Express your answer using three significant figures.
θNe = ∘
Part C
Calculate the angle for the first-order diffraction line of third source (argon).
Express your answer using three significant figures.
θAr = ∘
Physics
1 answer:
shtirl [24]3 years ago
6 0

Answer:

I can help

Explanation:

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If a ball is launched horizontally at 40 m/s
vaieri [72.5K]

Answer:

40m/s

Explanation:

The horizontal component of velocity remains constant because there are no external forces in that direction

By applying motion equations, V= U+ at

where ,

  • v - final velocity
  • u - initial velocity
  • a-acceleration
  • t - time

v = u +at

As no force act on the ball ( we neglect air resistance here) no acceleration is seen,

So v = u = 40m/s

4 0
3 years ago
Can someone give me an objective and subjective statement example please
shusha [124]

Answer:

Objective: It is raining. Subjective: I love the rain!

Explanation:

Anything objective sticks to the facts, but anything subjective has feelings. Objective and subjective are opposites.

(Hope this helps can I pls have brainlist (crown)☺️)

7 0
2 years ago
The closer together a magnets field lines are,
elena55 [62]
The stronger they will be
4 0
3 years ago
An airplane flying at an altitude of 6 miles passes directly over a radar antenna. When the airplane is 10 miles away (s = 10),
Novosadov [1.4K]

Answer:

Explanation:

Given

altitude of the Plane h=6\ miles

When Airplane is s=10\ miles away

Distance is changing at the rate of \frac{\mathrm{d} s}{\mathrm{d} t}=290\ mph

From diagram we can write as

h^2+x^2=s^2

differentiate above equation w.r.t time

2h\frac{\mathrm{d} h}{\mathrm{d} t}+2x\frac{\mathrm{d} x}{\mathrm{d} t}=2s\frac{\mathrm{d} s}{\mathrm{d} t}

as altitude is not changing therefore \frac{\mathrm{d} h}{\mathrm{d} t}=0

0+x\frac{\mathrm{d} x}{\mathrm{d} t}=s\frac{\mathrm{d} s}{\mathrm{d} t}

at s=10\ miles\ and\ h=6\ miles

substitute the value we get x=\sqrt{10^2-6^2}=8\ miles

8\times \frac{\mathrm{d} x}{\mathrm{d} t}=10\times 290

\frac{\mathrm{d} x}{\mathrm{d} t}=362.5\ mph

5 0
3 years ago
Position vs Time
viktelen [127]

Answer: 1. the object is moving away from the origin

4. the object started at 2 meters

5. the object is traveling at a constant velocity

Explanation:

7 0
3 years ago
Read 2 more answers
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