i have no clue, sorry. jus tryna get points
Answer:
b) Gravity
Explanation:
Gravity acts all of the time, when you apply force to a projectile it has to be more than the forces of the gravity and air resistance together so the projectile can move, when the rock is at the top of its trajectory the force that you applied at the beginning is getting lost, so the other forces (air resistance and gravity) make the rock fall to the floor.
Answer:
10 kg
Explanation:
The mass of an object does not change even if the amount of gravtiy changes.
Answer:
See description
Explanation:
With the given information we have:
![x(t) = 1 + cos(t)\\ y(t)=sin(t)\\ \rho(x,y) = 3x](https://tex.z-dn.net/?f=x%28t%29%20%3D%201%20%2B%20cos%28t%29%5C%5C%20y%28t%29%3Dsin%28t%29%5C%5C%20%5Crho%28x%2Cy%29%20%3D%203x)
the interval is ![[0,\pi ]](https://tex.z-dn.net/?f=%5B0%2C%5Cpi%20%5D)
now the mass
has the given expression:
![m = \int \rho(x,y) dS](https://tex.z-dn.net/?f=m%20%3D%20%5Cint%20%5Crho%28x%2Cy%29%20dS)
we will use the formula for a line integral and let:
![dS=\sqrt{x'(t)^2 + y'(t)^2}=\sqrt{cos(t)^2 + sin(t)^2}dt=dt](https://tex.z-dn.net/?f=dS%3D%5Csqrt%7Bx%27%28t%29%5E2%20%2B%20y%27%28t%29%5E2%7D%3D%5Csqrt%7Bcos%28t%29%5E2%20%2B%20sin%28t%29%5E2%7Ddt%3Ddt)
therefore we have:
![m=\int \rho(x,y)dS=\int\limits^\pi_0 {3*x}dS=\int\limits^\pi _0{3*(1+cos(t))dS\\=\int\limits^\pi _0{3*(1+cos(t))dt](https://tex.z-dn.net/?f=m%3D%5Cint%20%5Crho%28x%2Cy%29dS%3D%5Cint%5Climits%5E%5Cpi_0%20%7B3%2Ax%7DdS%3D%5Cint%5Climits%5E%5Cpi%20_0%7B3%2A%281%2Bcos%28t%29%29dS%5C%5C%3D%5Cint%5Climits%5E%5Cpi%20_0%7B3%2A%281%2Bcos%28t%29%29dt)
we solve the integral:
![m=3*\int\limits^\pi _0{(1+cos(t))dt= 3*(t+sin(t))\limits^\pi _0=3*\pi=9.42](https://tex.z-dn.net/?f=m%3D3%2A%5Cint%5Climits%5E%5Cpi%20_0%7B%281%2Bcos%28t%29%29dt%3D%203%2A%28t%2Bsin%28t%29%29%5Climits%5E%5Cpi%20_0%3D3%2A%5Cpi%3D9.42)
can i sent you photo in social media