Answer:
L = 0.635m
Explanation:
This problem involves the concept of stationary waves in pipes. For pipes closed at one end,
The frequency f = nv/4L for n = 1,3,5....n
For pipes open at both ends
f = nv/2L for n = 1,2,3,4...n
Assuming the pipe is closed at one end and that velocity of sound is 343m/s in air. If we are right we will obtain a whole number for n.
The film solution can be found in the attachment below.
Answer:
The maximum value of the driving force is 1044.01 N.
Explanation:
Given that,
Weight of the object, W = 50 N
Force constant of the spring, k = 210 N/m
The system is undamped and is subjected to a harmonic driving force of frequency 11.5 Hz.
Amplitude, A = 4 cm
We need to find the maximum value of the driving force. The force is given by the product of mass and maximum acceleration as :
.....(1)
A is amplitude
m is mass,
is angular frequency
Angular frequency is given by :
Equation (1) becomes :
So, the maximum value of the driving force is 1044.01 N.