Answer:
solution is
[-3,-1]
Step-by-step explanation:
we are given
![|10x+20|\leq 10](https://tex.z-dn.net/?f=%7C10x%2B20%7C%5Cleq%2010)
Firstly, we will find critical values
so, let's assume it is equal
![|10x+20|= 10](https://tex.z-dn.net/?f=%7C10x%2B20%7C%3D%2010)
now, we can break absolute sign
For
:
![-(10x+20)= 10](https://tex.z-dn.net/?f=-%2810x%2B20%29%3D%2010)
we can solve for x
![-10x-20= 10](https://tex.z-dn.net/?f=-10x-20%3D%2010)
Add both sides by 20
![-10x-20+20= 10+20](https://tex.z-dn.net/?f=-10x-20%2B20%3D%2010%2B20)
![-10x= 30](https://tex.z-dn.net/?f=-10x%3D%2030)
Divide both sides by -10
and we get
![x=-3](https://tex.z-dn.net/?f=x%3D-3)
For
:
![(10x+20)= 10](https://tex.z-dn.net/?f=%2810x%2B20%29%3D%2010)
we can solve for x
![10x+20= 10](https://tex.z-dn.net/?f=10x%2B20%3D%2010)
Subtract both sides by 20
![10x+20-20= 10-20](https://tex.z-dn.net/?f=10x%2B20-20%3D%2010-20)
![10x= -10](https://tex.z-dn.net/?f=10x%3D%20-10)
Divide both sides by 10
and we get
![x=-1](https://tex.z-dn.net/?f=x%3D-1)
so, critical values are
![x=-3](https://tex.z-dn.net/?f=x%3D-3)
![x=-1](https://tex.z-dn.net/?f=x%3D-1)
now, we can draw a number line and locate these values
and then we can check inequality on each intervals
For
:
We can select any random value from this interval and plug that in inequality
and we get
we can plug x=-5
![|10\times -5+20|\leq 10](https://tex.z-dn.net/?f=%7C10%5Ctimes%20-5%2B20%7C%5Cleq%2010)
![|-50+20|\leq 10](https://tex.z-dn.net/?f=%7C-50%2B20%7C%5Cleq%2010)
![30\leq 10](https://tex.z-dn.net/?f=30%5Cleq%2010)
so, this is FALSE
For
:
We can select any random value from this interval and plug that in inequality
and we get
we can plug x=-2
![|10\times -2+20|\leq 10](https://tex.z-dn.net/?f=%7C10%5Ctimes%20-2%2B20%7C%5Cleq%2010)
![|-20+20|\leq 10](https://tex.z-dn.net/?f=%7C-20%2B20%7C%5Cleq%2010)
![0\leq 10](https://tex.z-dn.net/?f=0%5Cleq%2010)
so, this is TRUE
For
:
We can select any random value from this interval and plug that in inequality
and we get
we can plug x=0
![|10\times 0+20|\leq 10](https://tex.z-dn.net/?f=%7C10%5Ctimes%200%2B20%7C%5Cleq%2010)
![|0+20|\leq 10](https://tex.z-dn.net/?f=%7C0%2B20%7C%5Cleq%2010)
![20\leq 10](https://tex.z-dn.net/?f=20%5Cleq%2010)
so, this is FALSE
so, solution is
[-3,-1]
281 gallons/ 60 min= 4.683 gallon per min
4.683 gallon per min * 94 hours= 440.23 gallons
Answer: 440.23 Gallons
Simple interest,
FV=P(1+ni)
FV=future value=2500
P=present value, invested amount
n=number of years, =3
i=annual interest rate, =0.095
2500=P(1+3(0.095))
Solve for P.
We have a sequence that meets the given criteria, and with that information, we want to get the sum of all the terms in the sequence.
We will see that the sum tends to infinity.
So we have 5 terms;
A, B, C, D, E.
We know that the sum of each term and its neighboring terms is 15 or 25.
then:
- A + B + C = 15 or 25
- B + C + D = 15 or 25
- C + D + E = 15 or 25
Now, we want to find the sum of all the terms in the sequence (not only the 5 given).
Then let's assume we write the sum of infinite terms as:
![a_1 + a_2 + a_3 + a_4 + a_5 + a_6 + ...](https://tex.z-dn.net/?f=a_1%20%2B%20a_2%20%2B%20a_3%20%2B%20a_4%20%2B%20a_5%20%2B%20a_6%20%2B%20...)
Now we group that sum in pairs of 3 consecutive terms, so we get:
![(a_1 + a_2 + a_3) + (a_4 + a_5 + a_6) + ...](https://tex.z-dn.net/?f=%28a_1%20%2B%20a_2%20%2B%20a_3%29%20%2B%20%28a_4%20%2B%20a_5%20%2B%20a_6%29%20%2B%20...)
So we will have a sum of infinite of these, and each one of these is equal to 15 or 25 (both positive numbers). So when we sum that infinite times (even if we always have the smaller number, 15) the sum will tend to be infinite.
Then we have:
![(a_1 + a_2 + a_3) + (a_4 + a_5 + a_6) + ... \to \infty](https://tex.z-dn.net/?f=%28a_1%20%2B%20a_2%20%2B%20a_3%29%20%2B%20%28a_4%20%2B%20a_5%20%2B%20a_6%29%20%2B%20%20...%20%5Cto%20%5Cinfty)
If you want to learn more, you can read:
brainly.com/question/21885715
Rectangle A’B’C’D’ has a scale factor of 2 because it is two times bigger then the original rectangle ABCD after the dilation.