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1 year ago

Find ΔG° for the reactions in Problem 20.51 using ΔHf° and S° values.

Chemistry

1 answer:

pashok25 [27]1 year ago

3 0

The value of ΔG° (gibbs free energy change)of the given reaction is -1131.94kj .

Given ,

Balanced chemical equation is given by,

2Mg(s) + O2 (g) → 2MgO (s)

Here , the standard enthalpy of Mg and O2 gas are zero because they are in the most stable state .

thus , the value of ΔG°rxn is given by ,

ΔG°rxn = ΔG°(products ) - ΔG°(reactants )

ΔG°rxn = [2×(-565.97 )] - 0

ΔG°rxn = 2×(-565.97)

ΔG°rxn = -1131.94kj

Hence , the value of ΔG° of the given reaction is -1131.94kj .

<h3>What is a balance chemical reaction ?</h3>

A balanced chemical reaction is a type of reaction which include the reactants and products in same amount i.e. the no of mole on both side of the reaction is remains same or balanced .

Learn more about chemical reaction here :

brainly.com/question/1893305

#SPJ4

Disclaimer :

incomplete question . here is the complete question .

Question :

Calculate ΔG° for the reaction using ΔG°f values :

2Mg(s) + O2 (g) → 2MgO (s)

Find the ΔG° for the reaction using ΔH°f and S° values .

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The metal which burns with a white dazzling flame is:

7nadin3 [17]

Answer:

<h3>Magnesium</h3>

Magnesium burns with a dazzling white flame to form magnesium oxide a powdery mass.

Explanation:

<h2>Hope this helps you !! </h2>

5 0

2 years ago

Read 2 more answers

aluminum has a specific heat of 0.897 j/g°C. how much heat is needed to raise the temperature of a 79 gram piece of aluminum 28°

frutty [35]

Answer:

Approximately 2000 J.

General Formulas and Concepts:

Thermodynamics

Specific Heat Formula: q = mcΔT

q is heat (in J)
m is mass (in g)
c is specific heat (in J/g °C)
ΔT is change in temperature (in °C or K)

Explanation:

Step 1: Define

Identify variables

[Given] c = 0.897 J/g °C

[Given] m = 79 g

[Given] ΔT = 28°C

[Solve] q

Step 2: Solve for q

Substitute in variables [Specific Heat Formula]: q = (79 g)(0.897 J/g °C)(28 °C)
Multiply [Cancel out units]: q = (70.863 J/°C)(28 °C)
Multiply [Cancel out units]: q = 1984.16 J

Step 3: Check

Follow sig fig rules and round. We are given 2 sig figs as our lowest.

1984.16 J ≈ 2000 J

6 0

2 years ago

If 450.0 mL of a 0.500 M solution is mixed with 200.0 mL of water, what is the molarity of the new

Oksana_A [137]

Answer:

Answer: A) .346 M

Explanation:

Given:

- 450 mL

- .5 M soln

-200 mL water

1) Convert mL to L

450 mL = .45 L

200 mL = .2 L

2) Find mols in solution

.5 M = x/.45 L

x = .225 mol

3) Find total volume of solution

.45 L + .2 L =.65 L

4) Find new molarity

molarity (M) = mols solute/ L solution

y = .225 mol (from step 2)/ .65 L (from step 3)

y = .346 M

Answer: A) .346 M

7 0

3 years ago

Nucleophilicity is a kinetic property. A higher nucleophilicity indicates that the nucleophile will easily donate its electrons

lord [1]

The rate constant (K) is related to activation energy (Ea), frequency factor (A) and temperature (T) in Kelvin by the equation

R = molar gas constant

K = A(e^(-Ea/RT))

Taking natural log of both sides

In K = In A - (Ea/RT)

In K = (-Ea/R)(1/T) + In A

Comparing this to the equation of a straight line; y = mx + c

y = In K, slope, m = (-Ea/R), x = (1/T) and intercept, c = In A

a) From the question, m = (-Ea/R) = -1.10 × (10^4) K

(-Ea/R) = -1.10 × (10^4) = -11000

R = 8.314 J/K.mol

Ea = -11000 × 8.314 = 91454 J/mol = 91.454 KJ/mol

b) c = In A = 33.5

A = e^33.5 = (3.54 × (10^14))/s

c) K = A(e^(-Ea/RT))

A = (3.54 × (10^14))/s, Ea = 91454 J/mol, T = 25°C = 298.15 K, R = 8.314 J/K.mol

K = (3.54 × (10^14))(e^(-91454/(8.314×298.15))) = 0.0336/s

QED!

3 0

3 years ago

The atomic number of an element:

Aleonysh [2.5K]

Answer:

I think #3 might be the answer .

Because in #1 atomic mass tells mass .

#4 Atomic number doesnot only tell about the electrons atom has

6 0

2 years ago