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Zina [86]
2 years ago
13

Elements found in the same periods of the modern periodic table are _____.

Chemistry
2 answers:
Dennis_Churaev [7]2 years ago
5 0
Try C I’m sorry if you get it wrong but I’m like 90% sure
juin [17]2 years ago
4 0
As far as I know, they are grouped according to increasing atomic number
You might be interested in
Who was the first person to propose that atoms existed?
Gennadij [26K]
Democritus was the first person to theorize the existence of atoms.
8 0
3 years ago
Read 2 more answers
Chemicals used in a laboratory investigation must be safely discarded. Which method is the safest way to dispose of chemicals at
Tema [17]

Answer:

Disposing of the discarded chemicals can be done by certain sfae methods mention as follows:

Explanation:

Most of the chemical wastes are dispose through the EHS waste program. Organic chemicals and solvents that can not be drain should be closed in a tight fitted container that has label on it as Hazardous waste, including strong acid and corrosive liquids.

Recycling of these chemicals and incineration is also use for the industrial chemical waste under professional guidance. Incineration is the process of burning chemicals in to ash through high thermal burning.

7 0
3 years ago
hich metal will displace nickel in a compound? A. Arsenic B. Tin C. Zinc D. Platinum
Bess [88]
Hello there,

The answer to your question is:

C. Zinc

Hope this answer helps you.
7 0
3 years ago
Hurry PLEASE HELP!
avanturin [10]

B. 11,540

<h3>Further explanation </h3>

The atomic nucleus can experience decay into 2 particles or more due to the instability of its atomic nucleus.  

Usually radioactive elements have an unstable atomic nucleus.  

General formulas used in decay:  

\large{\boxed{\bold{N_t=N_0(\dfrac{1}{2})^{t/t\frac{1}{2} }}}

T = duration of decay  

t 1/2 = half-life  

N₀ = the number of initial radioactive atoms  

Nt = the number of radioactive atoms left after decaying during T time  

Nt=25 g

No=100 g

t1/2=5770 years

\tt 25=100\dfrac{1}{2}^{T/5770}\\\\\dfrac{1}{4}=\dfrac{1}{2}^{T/5770}\\\\2=T/5770\rightarrowT=11540~years

7 0
3 years ago
Determine the oxidation number of each element in these compounds or ions. (a) au2(seo4)3 (gold(iii) selenate) au = se = o = (b)
Stels [109]
<span>                                                    Au</span>₂(SeO₄)₃

                                         O = -2 × 4 = -8
                                             Se  =  + 6
So,
                                            (+6 - 8) = -2

Means (SeO₄) contains -2 charge, Now multiply -2 by 3
                                             
                                             -2 ₓ 3 = -6
Means,
                             Au₂ + (-6) = 0
               
                            Au₂  = +6
Or,
                            Au  =  6 / 2

                            Au  = +3
Result:
                            Au  =  +3
                            Se  =  +6
                            O   =  -2

                                                      Ni(CN)₂


Cyanide (CN⁻) contains -1 charge,
So,
                              N  =  -3
                              C  =  +2
Then,
                                         Ni + (-1)₂  =  0

                                               Ni - 2  =  0
Or,
                                                     Ni =  +2
Result:
                            N  =  -3
                            C  =  +2
                           Ni  =  +2




6 0
3 years ago
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